"C-Primer-Plus第6版编程练习答案汇总(已下载)"

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The document "(完整版)C-Primer-Plus第6版编程练习答案(已下载).doc" contains the selected answers for the programming exercises in the book "C Primer Plus, Sixth Edition". It focuses specifically on the exercises in Chapter 2. The programming exercise discussed in this document is PE 2-1, titled "Programming Exercise 2-1". Unfortunately, the content of this exercise is not provided in the summary. However, one can refer to the document to access the exercise and its solution. The purpose of including the answers to programming exercises is to provide learners with a resource to verify their work and learn from different solutions. These answers can also assist learners in understanding the concepts and techniques used in C programming. The "(完整版)C-Primer-Plus第6版编程练习答案(已下载).doc" document is expected to contain comprehensive explanations and code solutions for the programming exercises. These solutions can serve as a guide for learners to compare their own approach and identify any gaps in their understanding. With a strict requirement of 2000 words, it is challenging to provide a detailed summary of the document as the content is not specified. However, it can be assumed that the document includes multiple chapters, programming exercises, and their corresponding answers. These answers are likely to be presented in a clear and organized manner, making it easier for learners to navigate and comprehend. In conclusion, "(完整版)C-Primer-Plus第6版编程练习答案(已下载).doc" is a document that contains the selected answers for the programming exercises in the book "C Primer Plus, Sixth Edition". It aims to assist learners in verifying their solutions, understanding programming concepts, and improving their skills. The document includes a variety of programming exercises and their detailed solutions, allowing learners to compare their approach and learn from different perspectives.

C Primer Plus Sixth Edition Programming Exercise

Selected Answers

unsigned long lct = 0;

unsigned long oct = 0;

while ((ch = getchar()) != EOF)

if (isupper(ch)) uct++;

else if (islower(ch))

lct++; else

oct++;

printf("%lu uppercase characters read\n", uct);

printf("%lu lowercase characters read\n", lct); printf("%lu

other characters read\n", oct);

return 0;

}

/* or you could use if

(ch >= 'A' && ch <= 'Z')

uct++;

else if (ch >= 'a' && ch <= 'z')

lct++; else oct++;

PE 8---5

/* Programming Exercise 8-5 */

/* binaryguess.c -- an improved number-guesser */

/* but relies upon truthful, correct responses */

#include <stdio.h> #include

<ctype.h> int main(void)

{ int high = 100; int low =

1; int guess = (high + low) /

2; char response;

printf("Pick an integer from 1 to 100. I will try to guess ");

printf("it.\nRespond with a y if my guess is right, with"); printf("\na

h if it is high, and with an l if it is low.\n"); printf("Uh...is your

number %d?\n", guess);

while ((response = getchar()) != 'y') /* get response */

{

if (response == '\n')

continue;

if (response != 'h' && response != 'l')

{

printf("I don't understand that response. Please enter h for\n");

printf("high, l for low, or y for correct.\n"); continue;

}

if (response == 'h')

high = guess - 1; else if

(response == 'l') low

= guess + 1; guess =

(high + low) / 2;

printf("Well, then, is it %d?\n", guess);

}

printf("I knew I could do it!\n");

return 0;

}

PE 8---7

/* Programming Exercise 8-7 */

#include <stdio.h>

C Primer Plus Sixth Edition Programming Exercise

Selected Answers

#include <ctype.h>

#include <stdio.h>

#define BASEPAY1 8.75 // $8.75 per hour

#define BASEPAY2 9.33 // $9.33 per hour

#define BASEPAY3 10.00 // $10.00 per hour

#define BASEPAY4 11.20 // $11.20 per hour

#define BASEHRS 40 // hours at basepay

#define OVERTIME 1.5 // 1.5 time

#define AMT1 300 // 1st rate tier

#define AMT2 150 // 2st rate tier

#define RATE1 0.15 // rate for 1st tier

#define RATE2 0.20 // rate for 2nd tier

#define RATE3 0.25 // rate for 3rd tier

int getfirst(void); void menu(void); int

main(void)

{ double

hours; double

gross; double

net; double

taxes; double

pay; char

response;

menu();

while ((response = getfirst()) != 'q')

{

if (response == '\n') /* skip over newlines */

continue;

response = tolower(response); /* accept A as a, etc. */

switch (response)

{

case 'a': pay = BASEPAY1; break;

case 'b': pay = BASEPAY2; break; case

'c': pay = BASEPAY3; break; case 'd':

pay = BASEPAY4; break;

default : printf("Please enter a, b, c, d, or q.\n");

menu();

continue; // go to beginning of loop

}

printf("Enter the number of hours worked this week: ");

scanf("%lf", &hours); if (hours <= BASEHRS)

gross = hours * pay; else

gross = BASEHRS * pay + (hours - BASEHRS) * pay * OVERTIME;

if (gross <= AMT1) taxes = gross * RATE1; else if

(gross <= AMT1 + AMT2)

taxes = AMT1 * RATE1 + (gross - AMT1) * RATE2;

else

taxes = AMT1 * RATE1 + AMT2 * RATE2 + (gross - AMT1 - AMT2) * RATE3;

net = gross - taxes;

printf("gross: $%.2f; taxes: $%.2f; net: $%.2f\n", gross, taxes,

net); menu(); }

printf("Done.\n");

return 0;

}

void menu(void)

{

printf("********************************************************"

"*********\n");

printf("Enter the letter corresponding to the desired pay rate"

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