CK140桌面型数控车床：迷你加工利器

CK6163型数控机床设计说明.doc

CK6163型数控车床主传动系统设计论文.doc

1.下列属于数控铁床的机床型号是( A.CK6140 B.XK714C C.SK—DX5060 2.数控机床对刀使用的坐标系是( ） A.工作坐标系 B.绝对坐标系 C.相对坐标系D.机床坐标系 3.根据加工零件图样选定的编制零件程序的原点是( A.机床原点 B.编程原点C.加工原点D.刀具原点 4.编程原点应尽量选择在零件的 1设计基准2工艺基准3定位基准 A.12B.34C.①③D.②④ 5.程序原点是刀具(刀尖)在加工程序执行时的起始点吗()？ A.是 B.不是 C.不确定 6.提高数控车削加工效率最终目的是（ A.最短的刀轨路径 B.最少的程序数量 C.最短的加工时间 D.最低的刀具损耗 7.下述CAD/CAM技术中，属于CAD范畴的是（ 0 A.数控加工 B.几何造型 C.CAPP D.仿真加工 8. 数控装置发出的一个进给脉冲所对应的机床坐标轴的位移量称为( 9.A.脉冲间隔B.脉冲当量 C.脉冲宽度 D.脉冲频率 10.在数控车床坐标中，Z轴是：( 11.A.与主轴垂直的方向B.与主轴平行的方向C.主轴旋转的方向D.刀架旋中转的方向 12.进给功能字F后的数字通常表示( 3.A.每分钟进给量(mm/min)B.每秒钟进给量(mm/s) .每转进给量(r/min)D.螺纹螺距 mm 4.下列机床中，属于点位控制的机床是( 5.A.数控铁床 B.数控车床 C.数控磨床D.数控钻床 5.G01指令移动速度值是( )指定。

代码优化 private int calculateScore() { int singleChoiceScore = 0; int multiChoiceScore = 0; // 计算单选题得分 RadioGroup singleChoiceGroup = findViewById(R.id.rg_1); int selectedSingleChoiceId = singleChoiceGroup.getCheckedRadioButtonId(); if (selectedSingleChoiceId == R.id.rb_1) { singleChoiceScore = 50; } // 计算多选题得分 CheckBox ck1 = findViewById(R.id.ck_1); CheckBox ck2 = findViewById(R.id.ck_2); CheckBox ck3 = findViewById(R.id.ck_3); CheckBox ck4 = findViewById(R.id.ck_4); CheckBox ck5 = findViewById(R.id.ck_5); int checkedCount = 0; // 统计选中的选项数量 if (ck1.isChecked()) { checkedCount++; } if (ck2.isChecked()) { checkedCount++; } if (ck3.isChecked()) { checkedCount++; } if (ck4.isChecked()) { checkedCount++; } if (ck5.isChecked()) { checkedCount++; } if (checkedCount == 0) { multiChoiceScore = 0; } else if (checkedCount == 2) { multiChoiceScore = 20; } else if (checkedCount == 3) { multiChoiceScore = 30; } else if (checkedCount == 4) { multiChoiceScore = 50; } return singleChoiceScore + multiChoiceScore; } private String calculateGrade(int score) { if (score < 60) { return "不及格"; } else if (score < 70) { return "合格"; } else if (score < 90) { return "良好"; } else { return "优秀"; } }

IMP-00002: 无法打开 H:\鏈湴澶囦唤ERP銆丟PS鏁版嵁姹囨€籠YY\CK_CZZ_KHZQ\20230818\CK_CZZ_KHZQ20230818.dmp 进行读取 导入文件: EXPDAT.DMP>

Traceback (most recent call last): File "C:\Exam\12000137\CK\1317\Prog1.py", line 31, in <module> main() File "C:\Exam\12000137\CK\1317\Prog1.py", line 28, in main print('数位：%s\n输入的数字：%s\n逆序数字：%s' % (len(s), s, fun(s))) File "C:\Exam\12000137\CK\1317\Prog1.py", line 19, in fun return (m[len(m) - 1] + fun(m[:0])) File "C:\Exam\12000137\CK\1317\Prog1.py", line 16, in fun return m[0] IndexError: string index out of range

void game() { int seconds = 59; while() while (1) { cleardevice(); update(); putimage(zuoqishi + mouse.y * size, shangqishi + mouse.x * size, &bgs[2]); char key = _getch(); switch (key) { case 72: case 'W': case 'w': if (mouse.x - 1 >= 0 && mapp[mouse.x - 1][mouse.y] != 0&& mapp[mouse.x - 1][mouse.y] != 2) { mouse.x--; } else if (mapp[mouse.x - 1][mouse.y] == 2) { } break;//上 case 80: case 'S': case 's': if (mouse.x + 1 < ck && mapp[mouse.x + 1][mouse.y] != 0) { mouse.x++; } break;//下 case 75: case 'A': case 'a': if (mouse.y - 1 >= 0 && mapp[mouse.x][mouse.y - 1] != 0) { mouse.y--; } break;//左 case 77: case 'D': case 'd': if (mouse.y + 1 < ck && mapp[mouse.x][mouse.y + 1] != 0) { mouse.y++; } break;//右 } Sleep(1000); seconds--; cout << seconds << endl; } endgame(); }怎样完成这段代码使得在按键操作的同时进行1分钟的倒计时

下面是单步单维预测模型的数据结构，如果改为多步预测，结构如何修改： s = self.ps*self.skip + self.Ck-1 + self.h-1 X1 = np.zeros((self.n-s, self.w, self.m)) # short term dataset X2 = np.zeros((self.n-s, self.ps*self.Ck, self.m)) # long term dataset Y = np.zeros((self.n-s, self.m)) # output dataset for i in range(s, self.n): t = i-self.h+1 X1[i-s] = self.raw[t-self.w:t].copy() idx = [] for k in range(self.ps): # 执行4次，每次间隔skip长，取Ck=6， total = 4 * 6 = 24 idx = list(range(t-self.Ck-k*self.skip, t-k*self.skip)) + idx idx = np.array(idx, dtype=int) X2[i-s] = self.raw[idx].copy() Y[i-s] = self.raw[i].copy() return X1, X2, Y

$("#allclick").click(function(){ var ck=$(this).prop("checked"); $("[name='product']").eath(function(){ $(this).prop("checked",ck); }); });

讲解一下这段代码:5.ListCartServlet： package Session01; import javax.servlet.ServletException; import javax.servlet.annotation.WebServlet; import javax.servlet.http.HttpServlet; import javax.servlet.http.HttpServletRequest; import javax.servlet.http.HttpServletResponse; import javax.servlet.http.HttpSession; import java.io.IOException; import java.io.PrintWriter; import java.util.ArrayList; @WebServlet("/listCartServlet") public class ListCartServlet extends HttpServlet { @Override protected void doGet(HttpServletRequest req, HttpServletResponse resp) throws ServletException, IOException { resp.setContentType("text/html;charset=utf-8"); PrintWriter out=resp.getWriter(); HttpSession session=req.getSession(); ArrayList<Phone> cart =(ArrayList<Phone>) session.getAttribute("cart"); if (cart==null){ out.println("

暂时还没有购物车数据。

您选购的物品如下:

"+ck.getName()+""+ck.getPrice()+"

请修改输出，一个是LABEL输出，一个是特征输出 ： def _slice_multi(self): # self.n 是数据集总行数 # self.m 是列 s = self.ps*self.skip + self.Ck-1 + self.h-1 X1 = np.zeros((self.n-s, self.w, self.m)) # short term dataset X2 = np.zeros((self.n-s, self.ps*self.Ck, self.m)) # long term dataset Y = np.zeros((self.n-s, self.m)) # output dataset for i in range(s, self.n): t = i-self.h+1 X1[i-s] = self.raw[t-self.w:t].copy() idx = [] for k in range(self.ps): # 执行4次，每次间隔skip长，取Ck=6， total = 4 * 6 = 24 idx = list(range(t-self.Ck-k*self.skip, t-k*self.skip)) + idx idx = np.array(idx, dtype=int) X2[i-s] = self.raw[idx].copy() Y[i-s] = self.raw[i].copy() return X1, X2, Y

假设可用的面额 是c的方幂, c0 ,c1 ,c2 ,…,ck , k>=1. 说明贪心法可得最优解.

document.querySelectorAll('.ck:checked')

s = self.ps*self.skip + self.Ck-1 + self.h-1 num_time_steps = 5 X1 = np.zeros((self.n-s, self.w, self.m)) X2 = np.zeros((self.n-s, self.ps*self.Ck, self.m)) Y = np.zeros((self.n-s-num_time_steps+1, num_time_steps*self.m)) for i in range(s, self.n): t = i-self.h+1 X1[i-s] = self.raw[t-self.w:t].copy() idx = [] for k in range(self.ps): idx = list(range(t-self.Ck-k*self.skip, t-k*self.skip)) + idx idx = np.array(idx, dtype=int) X2[i-s] = self.raw[idx].copy() for i in range(s+num_time_steps-1, self.n): Y[i-s-num_time_steps+1] = self.raw[i-num_time_steps+1:i+1].copy().flatten() Y = Y[:, -5*self.m:]

请从新检查 ： s = self.ps*self.skip + self.Ck-1 + self.h-1 X1 = np.zeros((self.n-s, self.w, self.m)) # short term dataset X2 = np.zeros((self.n-s, self.ps*self.Ck, self.m)) # long term dataset predict_step = 6 Y = np.zeros((self.n-s, predict_step)) for i in range(s, self.n): t = i-self.h+1 X1[i-s] = self.raw[t-self.w:t].copy() idx = [] for k in range(self.ps): # 执行4次，每次间隔skip长，取Ck=6， total = 4 * 6 = 24 idx = list(range(t-self.Ck-k*self.skip, t-k*self.skip)) + idx idx = np.array(idx, dtype=int) X2[i-s] = self.raw[idx].copy() #Y[i-s] = self.raw[i].copy() Y[i-s] = self.raw[i : i+predict_step].copy() return X1, X2, Y

.\Objects\xiaoche.axf: Error: L6200E: Symbol shuifen_10 multiply defined (by ck.o and main.o).

Statement s = conn.createStatement(); ResultSet rs = s.executeQuery(sql_ck); while (rs.next()) { if (rs.getString("book_id").equals(bookId)) { pst = conn.prepareStatement("update thebook set book_num = ? where book_id = ?"); System.out.println(getBookNum(bookId)); bookNum +=getBookNum(bookId); pst.setInt(1, bookNum); pst.setString(2, bookId); if (pst.executeUpdate() > 0) { return true; } else { return false; } } } pst.executeUpdate();这些代码是什么意思

货架名称 货架编码 货架位置 货架类型 所属仓库id 备注 根据上述字段生成100条数据，其中货架类型：1-6，所属仓库id包括CK001 CK002 CK003 CK004 CK005 CK006 CK007 CK008 CK009 CK010 CK011 CK012 CK013 CK014 CK015 CK016 CK017 CK018 CK019 CK020

const dl_car = document.querySelectorAll('dl.car'); const ck_btn = dl_car.querySelectorAll('p.ck_btn');是什么意思

12306抢票脚本 - Bypass