C# 2010入门：ASP.NET 4基础之旅

Use the following codes as the beginning of your program. Write a sort program to sort these ten numbers from largest to smallest, then save them to memory. For ARMSim#, the sorted number also need to be displayed in the console and LCD screen (use the Embest Board Plug‐In). MOV r0, #0x00002000 MOV r1, #18 STR r1, [r0],#4 MOV r1, #6 STR r1, [r0],#4 MOV r1, #2 STR r1, [r0],#4 MOV r1, #8 STR r1, [r0],#4 MOV r1, #16 STR r1, [r0],#4 MOV r1, #10 STR r1, [r0],#4 MOV r1, #14 STR r1, [r0],#4 MOV r1, #4 STR r1, [r0],#4 MOV r1, #20 STR r1, [r0],#4 MOV r1, #12 STR r1, [r0],#4

Sure, here's a sample program in ARM assembly language that sorts the 10 numbers in descending order using the bubble sort algorithm and saves them to memory starting from the address 0x00002000....

Write a class named ProductSystem, which extends JFrame class. The appearance of the application looks like the following (as shown in Figure 1). 2. At the beginning, input name,price and number at three JTextField fields, then click “Add”button (event source), which binds to a method (event listener) that create a Product object (using name,price and number) and add it into ArrayList<Product>, at the same time display “Add Product xxx sucess!” in JTextArea on the GUI (as shown in Figure 2) 3. When click “Display” button, then read the records from ArrayList , and display the records in JTextArea on the GUI(as shown in Figure 3). 4. When click “Save to File” button, then write the records from ArrayList to file product.txt, at the same time display "file write success" in JTextArea on the GUI (as shown in Figure 4)

4. When click “Save to File” button, then write the records from ArrayList to file product.txt, at the same time display "file write success" in JTextArea on the GUI (as shown in Figure 4). ...

Use the following codes as the beginning of your program. Write a program to find the largest and smallest number. The largest and smallest number needs to be saved in register r7 and r8, respectively. For ARMSim#, these numbers also need to be displayed in the console and LCD screen (use the Embest Board Plug‐In). MOV r0, #0x00002000 MOV r1, #9 STR r1, [r0],#4 MOV r1, #3 STR r1, [r0],#4 MOV r1, #1 STR r1, [r0],#4 MOV r1, #4 STR r1, [r0],#4 MOV r1, #8 STR r1, [r0],#4 MOV r1, #5 STR r1, [r0],#4 MOV r1, #7 STR r1, [r0],#4 MOV r1, #2 STR r1, [r0],#4 MOV r1, #10 STR r1, [r0],#4 MOV r1, #6 STR r1, [r0],#4

After executing this code, the largest number will be saved in register r7 and the smallest number will be saved in register r8. To display these numbers on the console and LCD screen, you can use the...

Write a program to 1.Setup a simulating backing store in memory. Read the data from pdata.bin to this backing store. 2.Initialize a page table for process p, set the frame number to be -1 for each page, indicating that the page is not loaded into memory yet. 3.Read logical addresses one by one from la.txt. 4.For each logical address, a)if its page has been loaded into physical memory, simply find the frame number in the page table, then generate physical address, find and print out the physical address and data inside this address. b)if the page is used for the first time, i.e., in page table, its frame number is -1，then the page that contains this address should be loaded into a free frame in physical memory (RAM). Then update the page table by adding the frame number to the right index in the page table. Then repeat 4a). Assumption: 1.Assume the file la.txt includes the sequence of generated addresses from CPU. 2.Use a part of memory as backing store that store data for a process. 3.The backing store size is 128 bytes 4.The size of process p is 128 bytes. 5.The contents of p is included in a file pdata.bin which is a binary file. 6.Use a part of memory as RAM. The size of physical memory is 256 bytes, from 0 to 255. All the physical memory is available, allocating starting from beginning in sequence. That is, allocate frame 0 first, then frame 1, then frame 2…. 7.The size of a frame is 32 bytes, i.e., 5 bits for the offset in a frame, total number of frames is 8. At beginning, no page table is available for process p.

4. For each logical address, the program computes the page number and offset. 5. If the page is already loaded into physical memory (i.e., its frame number is not -1), the program computes the ...

根据以下要求编写一个python程序1. Description Ship of Fools is a simple classic dice game. It is played with five standard 6-faced dice by two or more players. - The goal of the game is to gather a 6, a 5 and a 4 (ship, captain and crew) in the mentioned order. - The sum of the two remaining dice (cargo) is preferred as high as possible. The player with the highest cargo score wins the round. Example: - In the first round turn, if a player rolls 6 4 3 3 1 (note we five dice at the beginning), the player can bank the 6 (ship), but the rest needs to be re-rolled since there is no 5. - In the second round turn, if the player rolls 6 5 4 4 (four dice, since the 6 from last turn is banked), the player can bank the 5 (captain) and the 4 (crew). The player has three choices for the remaining 6 and 4. The player can bank both and score 10 points, or re-roll one or two of the dice and hope for a higher score. - In the second round turn, if the player instead rolled 4 4 3 1, all dice needs to be re-rolled since there is no 5.程序需要包含一下几个类.The division of responsibility between the different classes is as follows. - Die: Responsible for handling randomly generated integer values between 1 and 6. - DiceCup: Handles five objects (dice) of class Die. Has the ability to bank and release dice individually. Can also roll dice that are not banked. - ShipOfFoolsGame: Responsible for the game logic and has the ability to play a round of the game resulting in a score. Also has a property that tells what accumulated score results in a winning state, for example 21. - Player: Responsible for the score of the individual player. Has the ability, given a game logic, play a round of a game. The gained score is accumulated in the attribute score. - PlayRoom: Responsible for handling a number of players and a game. Every round the room lets each player play, and afterwards check if any player has reached the winning score.

elif 4 in values and not crew: dice_cup.bank(values.index(4)) crew = True cargo = sum(dice_cup.get_unbanked_values()) return cargo class Player: def __init__(self): self.score = 0 def play...

# 5 请编写一代码计算以下字符串变量str1中每个单词出现的频率，并且按照频率从高到低的 # 顺序输出。 # 输出举例 ''' 'a':7 'the':7 'is': 5 'with': 4 ''' str1 = ''' Each rule begins with a name (which is the name defined by the rule) and ::=. A vertical bar (|) is used to separate alternatives; it is the least binding operator in this notation. A star () means zero or more repetitions of the preceding item; likewise, a plus (+) means one or more repetitions, and a phrase enclosed in square brackets ([ ]) means zero or one occurrences (in other words, the enclosed phrase is optional). The and + operators bind as tightly as possible; parentheses are used for grouping. Literal strings are enclosed in quotes. White space is only meaningful to separate tokens. Rules are normally contained on a single line; rules with many alternatives may be formatted alternatively with each line after the first beginning with a vertical bar. '''

'in': 4 'with': 4 'to': 4 'and': 3 'are': 3 'zero': 2 'more': 2 'one': 2 'occurrences': 2 '('which': 1 'name': 1 'defined': 1 'by': 1 'the': 1 'rule)': 1 '::.': 1 'A': 1 'vertical': 1 'bar': 1 '(|)': ...

## 5 请编写一代码计算以下字符串变量str1中每个单词出现的频率，并且按照频率从高到低的 # 顺序输出。 # 输出举例 ''' 'a':7 'the':7 'is': 5 'with': 4 ''' import re str1 = ''' Each rule begins with a name (which is the name defined by the rule) and ::=. A vertical bar (|) is used to separate alternatives; it is the least binding operator in this notation. A star () means zero or more repetitions of the preceding item; likewise, a plus (+) means one or more repetitions, and a phrase enclosed in square brackets ([ ]) means zero or one occurrences (in other words, the enclosed phrase is optional). The and + operators bind as tightly as possible; parentheses are used for grouping. Literal strings are enclosed in quotes. White space is only meaningful to separate tokens. Rules are normally contained on a single line; rules with many alternatives may be formatted alternatively with each line after the first beginning with a vertical bar. '''

'in': 4 'and': 4 'a': 3 'zero': 2 'more': 2 'occurrences': 2 'rule': 2 'the': 2 'enclosed': 2 'operators': 2 'as': 2 'possible': 2 'rules': 2 'with': 2 'each': 1 'begins': 1 'name': 1 'which': 1 '...

.net mvc epplus导出excel文档

// Set the stream position to the beginning stream.Position = 0; // Return the Excel file as a byte array var bytes = stream.ToArray(); Response.Clear(); Response.ContentType = "application/vnd...

移动应用和游戏的开发的参考文献

3. "Unity in Action: Multiplatform Game Development in C#" by Joe Hocking 4. "Learning Swift: Building Apps for macOS, iOS, and Beyond" by Jonathon Manning and Paris Buttfield-Addison 5. "Android ...

swap: sll $2, $5, 2 add $2, $4, $2 lw $15, 0($2) lw $16, 4($2) sw $16, 0($2) sw $15, 4($2)

2. add $2, $4, $2 - Adds the value in $4 to the value in $2 and stores the result back in $2. 3. lw $15, 0($2) - Loads the word at the memory location pointed to by the value in $2 into $15. 4. lw $16...

请编写一代码计算以下字符串变量str1中每个单词出现的频率，并且按照频率从高到低的顺序输出。str1 = ''' Each rule begins with a name (which is the name defined by the rule) and ::=. A vertical bar (|) is used to separate alternatives; it is the least binding operator in this notation. A star () means zero or more repetitions of the preceding item; likewise, a plus (+) means one or more repetitions, and a phrase enclosed in square brackets ([ ]) means zero or one occurrences (in other words, the enclosed phrase is optional). The and + operators bind as tightly as possible; parentheses are used for grouping. Literal strings are enclosed in quotes. White space is only meaningful to separate tokens. Rules are normally contained on a single line; rules with many alternatives may be formatted alternatively with each line after the first beginning with a vertical bar. '''

in: 4 is: 3 or: 3 means: 3 zero: 3 more: 3 repetitions: 3 of: 3 enclosed: 2 on: 2 single: 2 line: 2 with: 2 vertical: 2 bar: 2 used: 2 to: 2 operators: 2 are: 2 rules: 2 which: 2 by: 1 name: 1 defined...

--------- beginning of system 和 --------- beginning of main 区别

"--------- beginning of system" 和 "--------- beginning of main" 是在代码文件中的两个标记，用于区分系统代码和主要代码的不同部分。 "--------- beginning of system" 标记通常用于指示系统级别的代码，例如...

智慧旅游景区解决方案PPT(50页).pptx

智慧旅游解决方案利用云计算、物联网和移动互联网技术，通过便携终端设备，实现对旅游资源、经济、活动和旅游者信息的智能感知和发布。这种技术的应用旨在提升游客在旅游各个环节的体验，使他们能够轻松获取信息、规划行程、预订票务和安排食宿。智慧旅游平台为旅游管理部门、企业和游客提供服务，包括政策发布、行政管理、景区安全、游客流量统计分析、投诉反馈等。此外，平台还提供广告促销、库存信息、景点介绍、电子门票、社交互动等功能。智慧旅游的建设规划得到了国家政策的支持，如《国家中长期科技发展规划纲要》和国务院的《关于加快发展旅游业的意见》，这些政策强调了旅游信息服务平台的建设和信息化服务的重要性。随着技术的成熟和政策环境的优化，智慧旅游的时机已经到来。智慧旅游平台采用SaaS、PaaS和IaaS等云服务模式，提供简化的软件开发、测试和部署环境，实现资源的按需配置和快速部署。这些服务模式支持旅游企业、消费者和管理部门开发高性能、高可扩展的应用服务。平台还整合了旅游信息资源，提供了丰富的旅游产品创意平台和统一的旅游综合信息库。智慧旅游融合应用面向游客和景区景点主管机构，提供无线城市门户、智能导游、智能门票及优惠券、景区综合安防、车辆及停车场管理等服务。这些应用通过物联网和云计算技术，实现了旅游服务的智能化、个性化和协同化，提高了旅游服务的自由度和信息共享的动态性。智慧旅游的发展标志着旅游信息化建设的智能化和应用多样化趋势，多种技术和应用交叉渗透至旅游行业的各个方面，预示着全面的智慧旅游时代已经到来。智慧旅游不仅提升了游客的旅游体验，也为旅游管理和服务提供了高效的技术支持。

智慧旅游实景三维智慧景区建设方案PPT(70页).pptx

智慧旅游解决方案利用云计算、物联网和移动互联网技术，通过便携终端设备，实现对旅游资源、经济、活动和旅游者信息的智能感知和发布。这种技术的应用旨在提升游客在旅游各个环节的体验，使他们能够轻松获取信息、规划行程、预订票务和安排食宿。智慧旅游平台为旅游管理部门、企业和游客提供服务，包括政策发布、行政管理、景区安全、游客流量统计分析、投诉反馈等。此外，平台还提供广告促销、库存信息、景点介绍、电子门票、社交互动等功能。智慧旅游的建设规划得到了国家政策的支持，如《国家中长期科技发展规划纲要》和国务院的《关于加快发展旅游业的意见》，这些政策强调了旅游信息服务平台的建设和信息化服务的重要性。随着技术的成熟和政策环境的优化，智慧旅游的时机已经到来。智慧旅游平台采用SaaS、PaaS和IaaS等云服务模式，提供简化的软件开发、测试和部署环境，实现资源的按需配置和快速部署。这些服务模式支持旅游企业、消费者和管理部门开发高性能、高可扩展的应用服务。平台还整合了旅游信息资源，提供了丰富的旅游产品创意平台和统一的旅游综合信息库。智慧旅游融合应用面向游客和景区景点主管机构，提供无线城市门户、智能导游、智能门票及优惠券、景区综合安防、车辆及停车场管理等服务。这些应用通过物联网和云计算技术，实现了旅游服务的智能化、个性化和协同化，提高了旅游服务的自由度和信息共享的动态性。智慧旅游的发展标志着旅游信息化建设的智能化和应用多样化趋势，多种技术和应用交叉渗透至旅游行业的各个方面，预示着全面的智慧旅游时代已经到来。智慧旅游不仅提升了游客的旅游体验，也为旅游管理和服务提供了高效的技术支持。

基于深度学习实现的半监督学习例子.zip

深度学习是机器学习的一个子领域，它基于人工神经网络的研究，特别是利用多层次的神经网络来进行学习和模式识别。深度学习模型能够学习数据的高层次特征，这些特征对于图像和语音识别、自然语言处理、医学图像分析等应用至关重要。以下是深度学习的一些关键概念和组成部分： 1. **神经网络（Neural Networks）**：深度学习的基础是人工神经网络，它是由多个层组成的网络结构，包括输入层、隐藏层和输出层。每个层由多个神经元组成，神经元之间通过权重连接。 2. **前馈神经网络（Feedforward Neural Networks）**：这是最常见的神经网络类型，信息从输入层流向隐藏层，最终到达输出层。 3. **卷积神经网络（Convolutional Neural Networks, CNNs）**：这种网络特别适合处理具有网格结构的数据，如图像。它们使用卷积层来提取图像的特征。 4. **循环神经网络（Recurrent Neural Networks, RNNs）**：这种网络能够处理序列数据，如时间序列或自然语言，因为它们具有记忆功能，能够捕捉数据中的时间依赖性。 5. **长短期记忆网络（Long Short-Term Memory, LSTM）**：LSTM 是一种特殊的 RNN，它能够学习长期依赖关系，非常适合复杂的序列预测任务。 6. **生成对抗网络（Generative Adversarial Networks, GANs）**：由两个网络组成，一个生成器和一个判别器，它们相互竞争，生成器生成数据，判别器评估数据的真实性。 7. **深度学习框架**：如 TensorFlow、Keras、PyTorch 等，这些框架提供了构建、训练和部署深度学习模型的工具和库。 8. **激活函数（Activation Functions）**：如 ReLU、Sigmoid、Tanh 等，它们在神经网络中用于添加非线性，使得网络能够学习复杂的函数。 9. **损失函数（Loss Functions）**：用于评估模型的预测与真实值之间的差异，常见的损失函数包括均方误差（MSE）、交叉熵（Cross-Entropy）等。 10. **优化算法（Optimization Algorithms）**：如梯度下降（Gradient Descent）、随机梯度下降（SGD）、Adam 等，用于更新网络权重，以最小化损失函数。 11. **正则化（Regularization）**：技术如 Dropout、L1/L2 正则化等，用于防止模型过拟合。 12. **迁移学习（Transfer Learning）**：利用在一个任务上训练好的模型来提高另一个相关任务的性能。深度学习在许多领域都取得了显著的成就，但它也面临着一些挑战，如对大量数据的依赖、模型的解释性差、计算资源消耗大等。研究人员正在不断探索新的方法来解决这些问题。

关于APx测试耳机音频的参数设置及步骤关于APx测试耳机音频的参数设置及步骤

jQuery背景可滑动的导航菜单代码，鼠标经过导航时导航背景可滑动，兼容主流浏览器

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C# 2010入门：ASP.NET 4基础之旅

.net mvc epplus导出excel文档

移动应用和游戏的开发的参考文献

swap: sll $2, $5, 2 add $2, $4, $2 lw $15, 0($2) lw $16, 4($2) sw $16, 0($2) sw $15, 4($2)

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Cannot resolve symbol 'URLEncoder'

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--------- beginning of system 和 --------- beginning of main 区别

智慧旅游景区解决方案PPT(50页).pptx

智慧旅游实景三维智慧景区建设方案PPT(70页).pptx

基于深度学习实现的半监督学习例子.zip

关于APx测试耳机音频的参数设置及步骤 关于APx测试耳机音频的参数设置及步骤

jQuery背景可滑动的导航菜单代码，鼠标经过导航时导航背景可滑动，兼容主流浏览器

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关于APx测试耳机音频的参数设置及步骤关于APx测试耳机音频的参数设置及步骤