Python实现比较两个列表(list)范围

Python实现比较两个列表实现比较两个列表(list)范围范围

主要介绍了Python实现比较两个列表(list)范围,本文根据一道题目实现解决代码,本文分别给出题目和解答源码,需

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有一道题： 比较两个列表范围，如果包含的话，返回TRUE，否则FALSE。 详细题目如下：

Create a function, this function receives two lists as parameters, each list indicates a scope of numbers, the function judges

whether list2 is included in list1.

Function signature:

differ_scope(list1, list2)

['23', '44-67', '12', '3', '20-90']

Return Values:

True - if all scopes and numbers indicated by list2 are included in list1.

False - if any scope or number in list2 is out of the range in list1.

Examples:

case1 - list1 = ['23', '44-67', '12', '3', '20-90']

list2 = ['22-34', '33', 45', '60-61']

differ_scope(list1, list2) == True

case2 - list1 = ['23', '44-67', '12', '3', '20-90']

list2 = ['22-34', '33', 45', '60-61', '100']

list1_not_ = [] #用于存放列表1正常的数字值，当然要用int()来转换

list1_yes_ = [] #用于存放列表1中范围值如 44-67

list1_final = [] #用于存放列表1中最终范围值 如:[1,2,3,4,5,6,7,8,9,10]

temp1 = []

list2_not_ = [] #用于存放列表2正常的数字值，当然要用int()来转换

list2_yes_ = [] #用于存放列表2中范围值如 44-67

list2_final= [] #用于存放列表2中最终范围值 如:[1,2,3,4,5,6,7,8,9,10]

temp2 = []

strlist = list1[i].split('-')

list1_yes_ = range(int(strlist[0]),int(strlist[1])+1)#让其生成一个范围列表

for each in list1_yes_: #FOR循环遍历所有符合条件的.

[temp1.append(each)]

else: #对列表1中正常的数字进行处理，放到list_not_列表中

list1_not_.append(int(list1[i]))#对列表1中进行处理，放到list_yes_

[temp1.append(i) for i in list1_not_ if not i in temp1]#去除重复项

list1_final = sorted(temp1) #比较后,排序,并放到list1_final列表中

print "list1_final value is:" + str(list1_final)#打印排序后最终list1_final列表

for each in list2_yes_:

[temp2.append(each)]

print "Temp2:" + str(temp2)

else: