Python实现嵌套列表及字典并按某一元素去重复功能示例

Python实现嵌套列表及字典并按某一元素去重复功能示例实现嵌套列表及字典并按某一元素去重复功能示例

主要介绍了Python实现嵌套列表及字典并按某一元素去重复功能,涉及Python列表嵌套列表、列表嵌套字典,及按

照某一元素去重复的相关操作方法,需要的朋友可以参考下

本文实例讲述了Python实现嵌套列表及字典并按某一元素去重复功能。分享给大家供大家参考，具体如下：

#! /usr/bin/env python

#coding=utf-8

class HostScheduler(object):

def __init__(self, resource_list):

k=0

for item in allResource:

#print 'item'

if dict['host'] != item['host']:

k=k+1

#continue

else:

break

if k == len(allResource):

allResource.append(dict)

#1、列表中嵌套列表。按元素‘b'实现去重复

l1=[['b',1],['b',2],['c',3],['a',1],['b',1],['b',1],]

l2=[]

l2.append(l1[0])

for data in l1:

#print len(l2)

k=0

for item in l2:

#print 'item'

if data[0] != item[0]:

#2、列表中嵌套字典。按键值host实现去重复

l3=[{'host':'compute21', 'cpu':2},{'host':'compute21', 'cpu':2},{'host':'compute22', 'cpu':2},

{'host':'compute23', 'cpu':2},{'host':'compute22', 'cpu':2},{'host':'compute23', 'cpu':2},

{'host':'compute24', 'cpu':2}]

l4=[]

l4.append(l3[0])

for dict in l3:

#print len(l4)

k=0

for item in l4:

if k == len(l4):

l4.append(dict)

print "l4: ",l4

if __name__ == '__main__':

#deleteRepeat()

resource_list=[{'host':'compute21', 'cpu':2},{'host':'compute21', 'cpu':2},{'host':'compute22', 'cpu':2},

{'host':'compute23', 'cpu':2},{'host':'compute22', 'cpu':2},{'host':'compute23', 'cpu':2},

{'host':'compute24', 'cpu':2}]

hostSchedule=HostScheduler(resource_list)

taskhost=hostSchedule.MergeHost()