Python使用Flask框架同时上传多个文件的方法_pythonflask接收文件

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Python使用使用Flask框架同时上传多个文件的方法框架同时上传多个文件的方法

主要介绍了Python使用Flask框架同时上传多个文件的方法,实例分析了Python中Flask框架操作文件实现上传的

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本文实例讲述了Python使用Flask框架同时上传多个文件的方法，分享给大家供大家参考。具体如下：

下面的演示代码带有详细的html页面和python代码

import os

# We'll render HTML templates and access data sent by POST

# using the request object from flask. Redirect and url_for

# will be used to redirect the user once the upload is done

# and send_from_directory will help us to send/show on the

# browser the file that the user just uploaded

from flask import Flask, render_template, request, redirect, url_for, send_from_directory

from werkzeug import secure_filename

# Initialize the Flask application

app = Flask(__name__)

# This is the path to the upload directory

app.config['UPLOAD_FOLDER'] = 'uploads/'

# These are the extension that we are accepting to be uploaded

app.config['ALLOWED_EXTENSIONS'] = set(['txt', 'pdf', 'png', 'jpg', 'jpeg', 'gif'])

# For a given file, return whether it's an allowed type or not

def allowed_file(filename):

return '.' in filename and \

filename.rsplit('.', 1)[1] in app.config['ALLOWED_EXTENSIONS']

# This route will show a form to perform an AJAX request

# jQuery is loaded to execute the request and update the

# value of the operation

@app.route('/')

def index():

return render_template('index.html')

# Route that will process the file upload

@app.route('/upload', methods=['POST'])

def upload():

# Get the name of the uploaded files

uploaded_files = request.files.getlist("file[]")

filenames = []

for file in uploaded_files:

# Check if the file is one of the allowed types/extensions

if file and allowed_file(file.filename):

# Make the filename safe, remove unsupported chars

filename = secure_filename(file.filename)

# Move the file form the temporal folder to the upload

# folder we setup

file.save(os.path.join(app.config['UPLOAD_FOLDER'],filename))

# Save the filename into a list, we'll use it later

filenames.append(filename)

# Redirect the user to the uploaded_file route, which

# will basicaly show on the browser the uploaded file

# Load an html page with a link to each uploaded file

return render_template('upload.html', filenames=filenames)

# This route is expecting a parameter containing the name

# of a file. Then it will locate that file on the upload

# directory and show it on the browser, so if the user uploads

# an image, that image is going to be show after the upload

@app.route('/uploads/<filename>')

def uploaded_file(filename):

return send_from_directory(app.config['UPLOAD_FOLDER'],

filename)

if __name__ == '__main__':

app.run(

host="0.0.0.0",

port=int("80"),

debug=True

)

index.html代码

<!DOCTYPE html>

<head>

rel="stylesheet">

</head>

<body>

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