使用银行家算法解决死锁预防

#include <iostream>
using namespace std;
#define MAXPROCESS 50                        /*最大进程数*/
#define MAXRESOURCE 100                        /*最大资源数*/
int AVAILABLE[MAXRESOURCE];                    /*可用资源数组*/
int MAX[MAXPROCESS][MAXRESOURCE];            /*最大需求矩阵*/
int ALLOCATION[MAXPROCESS][MAXRESOURCE];    /*分配矩阵*/
int NEED[MAXPROCESS][MAXRESOURCE];            /*需求矩阵*/
int REQUEST[MAXPROCESS][MAXRESOURCE];        /*进程需要资源数*/
bool FINISH[MAXPROCESS];                        /*系统是否有足够的资源分配*/
int p[MAXPROCESS];                             /*记录序列*/
int m,n;                                    /*m个进程,n个资源*/
void Init();
bool Safe();
void Bank();
int main()
{
    Init();
    Safe();
    Bank();
}
void Init()                /*初始化算法*/
{
    int i,j;
    cout<<"\t---------------------------------------------------"<<endl;
    cout<<"\t||                                               ||"<<endl;
    cout<<"\t||                 银行家算法                    ||"<<endl;
    cout<<"\t||                                               ||"<<endl;
    cout<<"\t||                             计科04151  李宏   ||"<<endl;
    cout<<"\t||                                               ||"<<endl;

    cout<<"\t||                                  0415084211   ||"<<endl;
    cout<<"\t---------------------------------------------------"<<endl;
    cout<<"请输入进程的数目:";
    cin>>m;
    cout<<"请输入资源的种类:";
    cin>>n;
    cout<<"请输入每个进程最多所需的各资源数,按照"<<m<<"x"<<n<<"矩阵输入"<<endl;
    for(i=0;i<m;i++)
    for(j=0;j<n;j++)
    cin>>MAX[i][j];
    cout<<"请输入每个进程已分配的各资源数,也按照"<<m<<"x"<<n<<"矩阵输入"<<endl;
    for(i=0;i<m;i++)
    {
        for(j=0;j<n;j++)
        {
            cin>>ALLOCATION[i][j];
            NEED[i][j]=MAX[i][j]-ALLOCATION[i][j];
            if(NEED[i][j]<0)
            {
                cout<<"您输入的第"<<i+1<<"个进程所拥有的第"<<j+1<<"个资源数错误,请重新输入:"<<endl;
                j--;
                continue;
            }
        }
    }
    cout<<"请输入各个资源现有的数目:"<<endl;
    for(i=0;i<n;i++)
    {
        cin>>AVAILABLE[i];
    }