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首页iOS Apprentice 7: iOS 12, Xcode 10 & Swift 4.2 学习指南

iOS Apprentice 7: iOS 12, Xcode 10 & Swift 4.2 学习指南

ios开发

raywenderlich

Apprentice

Xcode

Swift

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iOS Apprentice 第七版是由 Fahim Farook 和 Matthijs Hollemans 合著，由知名教程网站 Raywenderlich 在 2018 年出版的一本专为 iOS 开发者打造的权威指南。本书针对的是 iOS 12 系统，结合了 Xcode 10 的新特性以及 Swift 4.2 的语言支持。作为 2019 年的最新版本，它提供了全面且深入的iOS应用程序开发教程，适合初学者和进阶开发者。本书的核心内容涵盖了iOS应用开发的基础到高级技术，包括但不限于用户界面设计、Swift语言基础、网络编程、数据存储、多线程处理、测试与调试等。Raywenderlich 的出品保证了内容的质量和实用性，通过清晰的步骤指导读者完成实际项目，帮助他们提升iOS开发技能。购买iOS Apprentice 的用户可以利用所获得的许可，无限制地在多个应用程序中使用或修改书中的源代码，这极大地便利了开发者在实际项目中应用所学知识。然而，需要强调的是，所有版权、商标权和法律责任的规定都得到了严格的保护。未经版权所有者书面许可，禁止任何形式的复制或分发书本内容和材料，包括文本、图像和源代码。该书提供的不仅仅是技术知识，还有对行业最佳实践的探讨，确保读者能够遵循苹果的设计指南和编码标准。此外，由于是基于Xcode 10，读者将能学习到现代开发工具的使用技巧，这对于理解和适应不断更新的iOS生态系统至关重要。 iOS Apprentice 第七版是一本既实用又系统化的iOS开发教程，无论是希望通过iOS开发开启职业生涯的新手，还是寻求技术升级的开发者，都能从中受益匪浅。它不仅传授技能，而且鼓励创新和持续学习，为iOS开发者的职业发展奠定了坚实的基础。

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Submit for review 1101.........................................................................................................

The end 1104.............................................................................................................................

Conclusion 1107...........................................................................

More Books You Might Enjoy 1108......................................

New to iOS or Swift? 1108...................................................................................................

Experienced iOS developer? 1110....................................................................................

Want to make games? 1123.................................................................................................

Want to learn Android or Kotlin? 1127...........................................................................

iOS Apprentice

raywenderlich.com

Book Source Code &

Forums

This book comes with the source code for the starter and completed projects for each

chapter. These resources are shipped with the digital edition you downloaded from

store.raywenderlich.com.

We’ve also set up an ofﬁcial forum for the book at forums.raywenderlich.com. This is a

great place to ask questions about the book or to submit any errors you may ﬁnd.

raywenderlich.com

Book Updates

Since you’ve purchased the digital edition version of this book, you get free access to

any updates we may make to the book!

The best way to get update notiﬁcations is to sign up for our monthly newsletter. This

includes a list of the tutorials that came out on raywenderlich.com that month, any

important news like book updates or new books, and a list of our favorite iOS

development links for that month. You can sign up, here: www.raywenderlich.com/

newsletter.

raywenderlich.com

About the Cover

Striped dolphins live to about 55-60 years of age, can travel in pods numbering in the

thousands and can dive to depths of 700 m to feed on ﬁsh, cephalopods and

crustaceans. Baby dolphins don't sleep for a full a month after they’re born. That puts

two or three sleepless nights spent debugging code into perspective, doesn't it?

raywenderlich.com

Section 1: Getting Started

This section introduces you to the ﬁrst of the four apps you'll build over the course of

this book — Bull's Eye.

As you progress through building the Bull's Eye app, the section will teach you how to

think like a programmer and how to plan your programming tasks. In addition, you'll

also learn how to use Xcode, Interface Builder and even the basics of coding for iOS.

While some of the concepts in this section might seem a bit basic, please do not skip

this section if you are new to iOS development — you will learn some fundamentals

which act as the building blocks for what you learn later.

This section contains the following chapters:

Chapter 1: Introduction

Chapter 2: The One-Button App

Chapter 3: Slider and Labels

Chapter 4: Outlets

Chapter 5: Rounds and Score

Chapter 6: Polish

Chapter 7: The New Look

Chapter 8: The Final App

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c语言实现：有一个师傅进程和三个学徒进程，每个学徒连续不断地组装产品，做一个产品需要A. B、C三种零件，这三个学徒分别掌握有A零件、B零件、C零件多个。要求完成以下功能: （1）师傅源源不断地供应上述三种零件，但他每次只将其中的两种零件放在桌子上（所放零件由rand%3函数生成的0-2之间的随机数决定)。 (2）具有另一零件的学徒就可以组装产品，且做完后给师傅发信号，然后师傅再拿出两种零件放在桌上。 3）每次只能有一个进程放入或取出零件。（4）利用同步与互斥的相关知识编写仿真系统实现以上过程，要能够清晰表达产品生产的全过程。

while (finished < 10) { // 组装10个产品 int type1 = rand() % N; int type2 = rand() % N; while (type1 == type2) { // 保证放的两种零件不同 type2 = rand() % N; } sem_wait(&mutex); // 互斥访问桌子 ...

有一个师傅进程和三个学徒进程，每个学徒连续不断地组装产品，做一个产品需要A. B、C三种零件，这三个学徒分别掌握有A零件、B零件、C零件多个。要求完成以下功能: （1）师傅源源不断地供应上述三种零件，但他每次只将其中的两种零件放在桌子上（所放零件由rand%3函数生成的0-2之间的随机数决定)。 (2）具有另一零件的学徒就可以组装产品，且做完后给师傅发信号，然后师傅再拿出两种零件放在桌上。 3）每次只能有一个进程放入或取出零件。（4）利用同步与互斥的相关知识编写仿真系统实现以上过程，要能够清晰表达产品生产的全过程。

t_apprentice3 = threading.Thread(target=apprentice, args=("Apprentice 3", False, True, True)) # 启动线程 t_master.start() t_apprentice1.start() t_apprentice2.start() t_apprentice3.start() # 等待线程...

Create a new class that writes to the included txt file. Use a BufferedWriter to write the following text to the file: What took you so long? Well, you know, Master, I couldn't find a speeder that I really liked... There he is. ...with an open cockpit and the right speed capabilities. If you spent as much time practicing your saber techniques as you did your wit, you'd rival Master Yoda as a swordsman. I thought I already did. Only in your mind, my very young apprentice.

Only in your mind, my very young apprentice."; try (BufferedWriter writer = new BufferedWriter(new FileWriter(fileName))) { writer.write(textToWrite); } catch (IOException e) { e.printStackTrace...

Create a new class that writes to the included txt file. Use a BufferedWriter to write the following text to the file: What tookyou so long? Well, you know, Master, I couldn'tfind a speeder that I really liked... There he is. ...with an open cockpit and the right speed capabilities. I thought I already did. Only in your mind, my veryyoung apprentice. Make sure that all the line breaks are correct. Hint: You can access the file via its relative path by just stating its name: conversation.txt. No need to have the complete path to the file.

writer.write("Only in your mind, my very young apprentice.\n"); writer.close(); } catch (IOException e) { e.printStackTrace(); } } } ``` This class creates a BufferedWriter that writes the text...

Create a file writing class Create a new class that writes to the included txt file. Use a BufferedWriter to write the following text to the file: “What took you so long? Well, you know, Master, I couldn't find a speeder that I really liked... There he is. ...with an open cockpit and the right speed capabilities. If you spent as much time practicing your saber techniques as you did your wit, you'd rival Master Yoda as a swordsman. I thought I already did. Only in your mind, my very young apprentice. ”Make sure that all the line breaks are correct. Hint: You can access the file via its relative path by just stating its name: conversation.txt. No need to have the complete path to the file.

bufferedWriter.write("Only in your mind, my very young apprentice."); bufferedWriter.close(); writer.close(); } catch (IOException e) { e.printStackTrace(); } } } ``` This code creates a new ...

Create a file writing class Create a new class that writes to the included txt file. Use a BufferedWriter to write the following text to the file: What took you so long? Well, you know, Master, I couldn't find a speeder that I really liked... There he is. ...with an open cockpit and the right speed capabilities. If you spent as much time practicing your saber techniques as you did your wit, you'd rival Master Yoda as a swordsman. I thought I already did. Only in your mind, my very young apprentice. Make sure that all the line breaks are correct. Hint: You can access the file via its relative path by just stating its name: conversation.txt. No need to have the complete path to the file.

writer.write("Only in your mind, my very young apprentice.\n"); writer.close(); } catch (IOException e) { System.out.println("An error occurred: " + e.getMessage()); } } } ``` This class ...

C语言：有一个师傅进程和三个学徒进程，每个学徒连续不断地组装产品，做一个产品需要A、B、C三种零件，这三个学徒分别掌握有A零件、B零件、C零件多个。要求完成以下功能：（1）师傅源源不断地供应上述三种零件，但他每次只将其中的两种零件放在桌子上(所放零件由rand % 3函数生成的0-2之间的随机数决定)。（2）具有另一零件的学徒就可以组装产品，且做完后给师傅发信号，然后师傅再拿出两种零件放在桌上。（3）每次只能有一个进程放入或取出零件。

#define MAX_ITEMS 10 // 最大库存量 #define NUM_THREADS 4 // 线程数 sem_t sem_a, sem_b, sem_c; // 三个信号量，分别代表三种零件 pthread_mutex_t mutex; // 互斥锁 int items = 0; // 当前库存量 void *...

用c语言写一个代码完成有一个师傅进程和三个学徒进程，每个学徒连续不断地组装产品，做一个产品需要A. B、C三种零件，这三个学徒分别掌握有A零件、B零件、C零件多个。要求完成以下功能: （1）师傅源源不断地供应上述三种零件，但他每次只将其中的两种零件放在桌子上（所放零件由rand%3函数生成的0-2之间的随机数决定)。 (2）具有另一零件的学徒就可以组装产品，且做完后给师傅发信号，然后师傅再拿出两种零件放在桌上。 3）每次只能有一个进程放入或取出零件。（4）利用同步与互斥的相关知识编写仿真系统实现以上过程，要能够清晰表达产品生产的全过程。

pthread_create(&apprentice_threads[i], NULL, apprentice, &part_ids[i]); } // 等待学徒进程结束 for (int i = 0; i ; i++) { pthread_join(apprentice_threads[i], NULL); } // 销毁信号量和互斥锁 ...

C语言代码：有一个师傅进程和三个学徒进程，每个学徒连续不断地组装产品，做一个产品需要A、B、C三种零件，这三个学徒分别掌握有A零件、B零件、C零件多个。要求完成以下功能：（1）师傅源源不断地供应上述三种零件，但他每次只将其中的两种零件放在桌子上(所放零件由rand % 3函数生成的0-2之间的随机数决定)。（2）具有另一零件的学徒就可以组装产品，且做完后给师傅发信号，然后师傅再拿出两种零件放在桌上。（3）每次只能有一个进程放入或取出零件。（4）利用同步与互斥的相关知识编写仿真系统实现以上过程，要能够清晰表达产品生产的全过程。

程序中，信号量 `sem_a`、`sem_b`、`sem_c` 分别表示 A、B、C 零件的数量，信号量 `sem_master` 表示师傅放入两种零件的信号，信号量 `sem_apprentice` 表示学徒组装成功的信号。师傅进程在循环中随机生成两种零件并...

C语言：有一个师傅进程和三个学徒进程，每个学徒连续不断地组装产品，做一个产品需要A、B、C三种零件，这三个学徒分别掌握有A零件、B零件、C零件多个。要求完成以下功能：（1）师傅源源不断地供应上述三种零件，但他每次只将其中的两种零件放在桌子上(所放零件由rand % 3函数生成的0-2之间的随机数决定)。（2）具有另一零件的学徒就可以组装产品，且做完后给师傅发信号，然后师傅再拿出两种零件放在桌上。（3）每次只能有一个进程放入或取出零件。

#define K 10 // 最多可组装的产品数 int parts[N] = {0}; // 零件库存 sem_t sems[N]; // 信号量数组 sem_t mutex; // 互斥信号量 int count = 0; // 已组装的产品数量 void* master(void* arg) { int i, j; ...

C语言实现：有一个师傅进程和三个学徒进程，每个学徒连续不断地组装产品，做一个产品需要A、B、C三种零件，这三个学徒分别掌握有A零件、B零件、C零件多个。要求完成以下功能：（1）师傅源源不断地供应上述三种零件，但他每次只将其中的两种零件放在桌子上(所放零件由rand % 3函数生成的0-2之间的随机数决定)。（2）具有另一零件的学徒就可以组装产品，且做完后给师傅发信号，然后师傅再拿出两种零件放在桌上。（3）每次只能有一个进程放入或取出零件。

C++：有一个师傅进程和三个学徒进程，每个学徒连续不断地组装产品，做一个产品需要A、B、C三种零件，这三个学徒分别掌握有A零件、B零件、C零件多个。要求完成以下功能：（1）师傅源源不断地供应上述三种零件，但他每次只将其中的两种零件放在桌子上(所放零件由rand % 3函数生成的0-2之间的随机数决定)。（2）具有另一零件的学徒就可以组装产品，且做完后给师傅发信号，然后师傅再拿出两种零件放在桌上。（3）每次只能有一个进程放入或取出零件。（4）利用同步与互斥的相关知识编写仿真系统实现以上过程，要能够清晰表达产品生产的全过程。

pthread_create(&apprentices[i], NULL, apprentice, &apprentice_args[i]); } while (1) { produce_parts(); usleep(500000); } return 0; } ``` 在上面的代码中，师傅进程用 `produce_parts` 函数来模拟...

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有一个师傅进程和三个学徒进程,每个学徒连续不断地组装产品,做一个产品需要A. B、C三种零件,这三个学徒分别掌握有A零件、B零件、C零件多个。 要求完成以下功能: (1)师傅源源不断地供应上述三种零件,但他每次只

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有一个师傅进程和三个学徒进程,每个学徒连续不断地组装产品,做一个产品需要A. B、C三种零件,这三个学徒分别掌握有A零件、B零件、C零件多个。要求完成以下功能: (1)师傅源源不断地供应上述三种零件,但他每次只