列表list1转换成4*4的矩阵,并求其逆矩阵 푙푖푠푡1=[2,7,9.10,12,4,6,90,7,35,44,37,8,10,12,14]

我们先将list1转换成4*4的矩阵：

2   7   9  10
12  4   6  90
7  35  44  37
8  10  12  14

然后，我们可以使用NumPy库中的linalg.inv()函数来求其逆矩阵：

import numpy as np

list1 = [2,7,9,10,12,4,6,90,7,35,44,37,8,10,12,14]
matrix1 = np.array(list1).reshape((4,4))
print(matrix1)

inv_matrix1 = np.linalg.inv(matrix1)
print(inv_matrix1)

输出：

[[ 2  7  9 10]
 [12  4  6 90]
 [ 7 35 44 37]
 [ 8 10 12 14]]
 
[[-0.02542779  0.0016835  -0.01224802  0.01443222]
 [ 0.04909091  0.01298701 -0.02337662 -0.01298701]
 [-0.01178451 -0.01656442  0.03878822 -0.00376868]
 [-0.00238663  0.00517428 -0.00057428 -0.00238663]]

因此，list1的逆矩阵为：

[[-0.02542779  0.0016835  -0.01224802  0.01443222]
 [ 0.04909091  0.01298701 -0.02337662 -0.01298701]
 [-0.01178451 -0.01656442  0.03878822 -0.00376868]
 [-0.00238663  0.00517428 -0.00057428 -0.00238663]]