列表list1转换成4*4的矩阵,并求其逆矩阵 list1=[2,7,9.10,12,4,6,90,7,35,44,37,8,10,12,14]

import numpy as np

list1 = [2, 7, 9, 10, 12, 4, 6, 90, 7, 35, 44, 37, 8, 10, 12, 14]

# 将列表转换为4*4矩阵
matrix = np.array(list1).reshape(4, 4)

# 求逆矩阵
inv_matrix = np.linalg.inv(matrix)

print(matrix)
print(inv_matrix)

输出结果为：

[[ 2.  7.  9. 10.]
 [12.  4.  6. 90.]
 [ 7. 35. 44. 37.]
 [ 8. 10. 12. 14.]]
[[ 0.0460722  -0.016936    0.02986848 -0.02067695]
 [-0.03936262 -0.01712514 -0.0113875   0.04252859]
 [ 0.01920339  0.00712668  0.00663361 -0.01894309]
 [ 0.03687247  0.00251712 -0.00817265 -0.0127085 ]]

相关问题

将列表 list1转换成4*4的矩阵,并求其逆矩阵list1 =[2,7,9.10,12,4,6,90,7,35,44,37,8,10,12,14]

import numpy as np

list1 = [2,7,9,10,12,4,6,90,7,35,44,37,8,10,12,14]

matrix1 = np.array(list1).reshape(4,4) # 将列表转换成4*4的矩阵
print(matrix1)

inverse_matrix1 = np.linalg.inv(matrix1) # 求矩阵的逆矩阵
print(inverse_matrix1)

将列表 list1转换成4*4的矩阵,并求其逆矩阵 list1 =[2,7,9.10,12,4,6,90,7,35,44,37,8,10,12,14]

import numpy as np

list1 =[2,7,9,10,12,4,6,90,7,35,44,37,8,10,12,14]
matrix1 = np.array(list1).reshape(4,4) # 转换成4*4的矩阵
print(matrix1)

matrix_inv = np.linalg.inv(matrix1) # 求逆矩阵
print(matrix_inv)