用MPI_Scatterv和MPI_Gatherv计算矩阵乘法
时间: 2024-03-31 15:31:53 浏览: 137
好的,下面是使用MPI_Scatterv和MPI_Gatherv来计算矩阵乘法的示例代码:
```c
#include <stdio.h>
#include <stdlib.h>
#include <mpi.h>
#define MATRIX_SIZE 4
int main(int argc, char* argv[]) {
int rank, size;
MPI_Init(&argc, &argv);
MPI_Comm_rank(MPI_COMM_WORLD, &rank);
MPI_Comm_size(MPI_COMM_WORLD, &size);
if (size != MATRIX_SIZE) {
printf("Error: the number of processes must be %d\n", MATRIX_SIZE);
MPI_Abort(MPI_COMM_WORLD, 1);
}
int matrix_a[MATRIX_SIZE][MATRIX_SIZE] = {
{1, 2, 3, 4},
{5, 6, 7, 8},
{9, 10, 11, 12},
{13, 14, 15, 16}
};
int matrix_b[MATRIX_SIZE][MATRIX_SIZE] = {
{1, 2, 3, 4},
{5, 6, 7, 8},
{9, 10, 11, 12},
{13, 14, 15, 16}
};
int local_matrix_a[MATRIX_SIZE][MATRIX_SIZE/MATRIX_SIZE];
int local_matrix_b[MATRIX_SIZE/MATRIX_SIZE][MATRIX_SIZE];
int local_matrix_c[MATRIX_SIZE/MATRIX_SIZE][MATRIX_SIZE/MATRIX_SIZE];
int sendcounts[MATRIX_SIZE];
int displs[MATRIX_SIZE];
// scatter matrix_a
for (int i = 0; i < MATRIX_SIZE; i++) {
int local_cols = MATRIX_SIZE / size;
sendcounts[i] = local_cols;
displs[i] = i * local_cols;
}
MPI_Scatterv(matrix_a, sendcounts, displs, MPI_INT, local_matrix_a, MATRIX_SIZE * MATRIX_SIZE / size, MPI_INT, 0, MPI_COMM_WORLD);
// scatter matrix_b
for (int i = 0; i < MATRIX_SIZE; i++) {
int local_rows = MATRIX_SIZE / size;
sendcounts[i] = local_rows;
displs[i] = i * local_rows;
}
MPI_Scatterv(matrix_b, sendcounts, displs, MPI_INT, local_matrix_b, MATRIX_SIZE * MATRIX_SIZE / size, MPI_INT, 0, MPI_COMM_WORLD);
// calculate local_matrix_c
for (int i = 0; i < MATRIX_SIZE/MATRIX_SIZE; i++) {
for (int j = 0; j < MATRIX_SIZE/MATRIX_SIZE; j++) {
local_matrix_c[i][j] = 0;
for (int k = 0; k < MATRIX_SIZE; k++) {
local_matrix_c[i][j] += local_matrix_a[i][k] * local_matrix_b[k][j];
}
}
}
// gather matrix_c
MPI_Gatherv(local_matrix_c, MATRIX_SIZE * MATRIX_SIZE / size, MPI_INT, matrix_c, sendcounts, displs, MPI_INT, 0, MPI_COMM_WORLD);
if (rank == 0) {
printf("Matrix C:\n");
for (int i = 0; i < MATRIX_SIZE; i++) {
for (int j = 0; j < MATRIX_SIZE; j++) {
printf("%d ", matrix_c[i][j]);
}
printf("\n");
}
}
MPI_Finalize();
return 0;
}
```
在这个示例中,矩阵A和矩阵B都是4x4的矩阵。我们将使用4个进程来计算矩阵乘积,每个进程计算结果的一部分。使用MPI_Scatterv将矩阵A和矩阵B分发到各个进程中,并使用MPI_Gatherv将结果收集回主进程。在每个进程中,我们使用双重循环计算局部矩阵的乘积,并将结果存储在局部矩阵C中。最后,我们在主进程中输出完整的矩阵C。
阅读全文