Suppose int i = 5, which of the following can be used as an index for array double[ ] t = new double[100]? (Choose all that apply.) _______ A) i B) i + 10 C) (int)(Math.random() * 100)) D) Math.random() * 100 E) i + 6.5

A) i 可以作为数组 t 的索引，因为它是一个整数。
B) i + 10 可以作为数组 t 的索引，因为它是一个整数。
C) (int)(Math.random() * 100)) 可以作为数组 t 的索引，因为它是一个整数。
E) i + 6.5 不能作为数组 t 的索引，因为它是一个浮点数，而数组的索引必须是整数类型。
D) Math.random() * 100 不能作为数组 t 的索引，因为它是一个浮点数，而数组的索引必须是整数类型。

所以，可以作为索引的选项是 A)、B)、C)。

相关问题

3) Suppose that one hotel only has an android charging interface, and now the customer only has an ios charger, which cannot be used directly. According to following code, try to: (1) What kind of design pattern can be used to solve the compatibility problem? (2) Draw the corresponding class diagram of the code.

1) The adapter design pattern can be used to solve the compatibility problem.

2) Here is the corresponding class diagram:

    +----------------------+       +----------------------+       +-----------------------+
    |      IOSCharger      |       |    AndroidInterface   |       |   AndroidChargerAdapter |
    +----------------------+       +----------------------+       +-----------------------+
    |                      |       |                      |       |                       |
    | +chargeWithIOS()     |       | +chargeWithAndroid() |       | +chargeWithIOS()       |
    |                      |       |                      |       |                       |
    +----------------------+       +----------------------+       +-----------------------+

In this diagram, `IOSCharger` and `AndroidInterface` are two existing classes that are incompatible with each other. The `AndroidChargerAdapter` class acts as an adapter that bridges the gap between the two incompatible classes. It implements the `AndroidInterface` interface and adapts it to work with the `IOSCharger` class by defining a `chargeWithIOS()` method.

.Let color be the following structure: struct color int red;int green;int blue;};Suppose the resolution of the picture is 300 x 300 that is, you need to create a two-dimensional array of 300 x 300 pixels, each of which stores information in three channels: red, green, and blue. The color value is a random integer.

To create a two-dimensional array of 300 x 300 pixels, each storing information in the three color channels, we can use the following code in C++:

struct color {
    int red;
    int green;
    int blue;
};

const int width = 300;
const int height = 300;

color image[height][width];

// To initialize the color values with random integers between 0 and 255
for (int i = 0; i < height; i++) {
    for (int j = 0; j < width; j++) {
        image[i][j].red = rand() % 256;
        image[i][j].green = rand() % 256;
        image[i][j].blue = rand() % 256;
    }
}

This code defines a struct `color` that has three integer fields `red`, `green`, and `blue`. We then define two constants, `width` and `height`, to specify the dimensions of the image. The two-dimensional array `image` is then created with dimensions `height` and `width`, with each element of the array storing a `color` struct.

To initialize the color values with random integers between 0 and 255, we use a nested loop to iterate over each element of the array and set its `red`, `green`, and `blue` fields to a random integer between 0 and 255 using the `rand()` function.