1.建立一个链表将实训12第2题定义的 学生数据存入链表，并读出显示出来。（10分） 数据为： { {"2020B200301","刘滨","男",18,{2020,9,20},70,85}, {"2020B200302","阚美娟","女",17,{2020,9,20},87,95}, {"2020B200303","胡大勇","男",17,{2020,9,20},69,80}, {"2020B200305","黎丽","女",18,{2020,9,20},68,88}, {"2020B200309","金鑫","男",19,{2019,9,1},90,85} }.打印链表中的成绩1和成绩2都大于等于70的记录，并计算各自的平均成绩后输出：

好的，我理解了你的要求。以下是实现链表存储学生数据并输出符合要求的记录的示例代码，你可以参考：

#include <iostream>
#include <string>
using namespace std;

// 定义学生结构体
struct Student {
    string id;
    string name;
    string gender;
    int age;
    int birthday[3];
    int score1;
    int score2;
    Student *next;
};

// 求平均分函数
double calculateAverage(int score1, int score2) {
    return (score1 + score2) / 2.0;
}

int main() {
    // 存储学生数据
    Student stuArr[] = {
        {"2020B200301","刘滨","男",18,{2020,9,20},70,85,NULL},
        {"2020B200302","阚美娟","女",17,{2020,9,20},87,95,NULL},
        {"2020B200303","胡大勇","男",17,{2020,9,20},69,80,NULL},
        {"2020B200305","黎丽","女",18,{2020,9,20},68,88,NULL},
        {"2020B200309","金鑫","男",19,{2019,9,1},90,85,NULL}
    };

    // 建立链表
    Student *head = new Student;
    head->next = NULL;
    Student *tail = head;
    for(int i = 0; i < 5; i++) {
        Student *newStu = new Student;
        newStu->id = stuArr[i].id;
        newStu->name = stuArr[i].name;
        newStu->gender = stuArr[i].gender;
        newStu->age = stuArr[i].age;
        for(int j = 0; j < 3; j++) {
            newStu->birthday[j] = stuArr[i].birthday[j];
        }
        newStu->score1 = stuArr[i].score1;
        newStu->score2 = stuArr[i].score2;
        newStu->next = NULL;
        tail->next = newStu;
        tail = newStu;
    }

    // 输出符合要求的记录并计算平均分
    Student *p = head->next;
    while(p != NULL) {
        if(p->score1 >= 70 && p->score2 >= 70) {
            double average = calculateAverage(p->score1, p->score2);
            cout << p->id << " " << p->name << " " << p->score1 << " " << p->score2 << " " << average << endl;
        }
        p = p->next;
    }

    return 0;
}

输出结果为：

2020B200301 刘滨 70 85 77.5
2020B200302 阚美娟 87 95 91
2020B200309 金鑫 90 85 87.5