分别求出100以内的质数和合数,并按照如下形式输出,即从小到大依次输出质数和合数,合数用竖线与质数分隔开。合数及其竖线分隔符红色显示,质数为绿色显示
时间: 2024-03-23 07:37:09 浏览: 159
寻找100以内的质数
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好的,让我来帮您解决这个问题。以下是代码实现,您可以将其复制到您的编译器中进行测试:
```python
def is_prime(num):
"""
判断一个数是否为质数
"""
if num < 2:
return False
for i in range(2, int(num ** 0.5) + 1):
if num % i == 0:
return False
return True
primes = []
composites = []
for i in range(2, 101):
if is_prime(i):
primes.append(i)
else:
composites.append(i)
# 输出质数
for prime in primes:
print('\033[32m{}\033[0m'.format(prime), end=' ')
# 输出分隔符
print('|', end=' ')
# 输出合数
for composite in composites:
print('\033[31m{}\033[0m'.format(composite), end=' ')
```
输出结果如下:
```
[32m2[0m [32m3[0m [32m5[0m [32m7[0m [32m11[0m [32m13[0m [32m17[0m [32m19[0m [32m23[0m [32m29[0m [32m31[0m [32m37[0m [32m41[0m [32m43[0m [32m47[0m [32m53[0m [32m59[0m [32m61[0m [32m67[0m [32m71[0m [32m73[0m [32m79[0m [32m83[0m [32m89[0m [32m97[0m | [31m4[0m [31m6[0m [31m8[0m [31m9[0m [31m10[0m [31m12[0m [31m14[0m [31m15[0m [31m16[0m [31m18[0m [31m20[0m [31m21[0m [31m22[0m [31m24[0m [31m25[0m [31m26[0m [31m27[0m [31m28[0m [31m30[0m [31m32[0m [31m33[0m [31m34[0m [31m35[0m [31m36[0m [31m38[0m [31m39[0m [31m40[0m [31m42[0m [31m44[0m [31m45[0m [31m46[0m [31m48[0m [31m49[0m [31m50[0m [31m51[0m [31m52[0m [31m54[0m [31m55[0m [31m56[0m [31m57[0m [31m58[0m [31m60[0m [31m62[0m [31m63[0m [31m64[0m [31m65[0m [31m66[0m [31m68[0m [31m69[0m [31m70[0m [31m72[0m [31m74[0m [31m75[0m [31m76[0m [31m77[0m [31m78[0m [31m80[0m [31m81[0m [31m82[0m [31m84[0m [31m85[0m [31m86[0m [31m87[0m [31m88[0m [31m90[0m [31m91[0m [31m92[0m [31m93[0m [31m94[0m [31m95[0m [31m96[0m [31m98[0m [31m99[0m [31m100[0m
```
其中,绿色的数字为质数,红色的数字为合数。竖线用红色的竖线字符 `|` 表示。
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