fib=[1,1] for i in range(2,31): fib.appened([i-1]+[i-2]) print(fib)
时间: 2023-12-19 08:03:47 浏览: 63
这段代码有一些语法错误,我猜测您想要生成斐波那契数列,并将其存储在列表fib中。正确的代码应该是这样的:
```
fib = [1, 1]
for i in range(2, 31):
fib.append(fib[i-1] + fib[i-2])
print(fib)
```
这段代码使用了for循环,从第二个位置开始遍历到第31个位置,每次将前两个元素相加并将结果添加到列表fib中。最后,打印出完整的斐波那契数列。
相关问题
fib = [1, 1] for i in range(2, 30): fib.append(fib[i-1] + fib[i-2]) print(fib)
这段代码存在语法错误,正确的代码应该是这样的:
```
fib = [1, 1]
for i in range(2, 30):
fib.append(fib[i-1] + fib[i-2])
print(fib)
```
这段代码的作用是生成斐波那契数列的前30项,并将结果打印出来。斐波那契数列是一组以递归的方式定义的数列,每一项都等于前两项的和,前两项分别为1和1。
def fib(n): a,b=1,1 for i in range(n-1): a,b=b,a+b return a print(fib(7)
As an AI language model, I can see that there is a syntax error in the code. The line "a,b=b,a" should have a comma instead of a Chinese full-width comma.
Here is the corrected code:
def fib(n):
a,b=1,1
for i in range(n-1):
a,b=b,a+b
return a
print(fib(7))
This code defines a function fib(n) that calculates the nth Fibonacci number. The function starts with the first two Fibonacci numbers (1 and 1), and then iteratively calculates the next number in the sequence by adding the previous two numbers. The function returns the nth Fibonacci number.
In this example, the function is called with n=7, so it calculates the 7th Fibonacci number, which is 13. The result is printed using the print() function.
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