python调用time库，用函数绘制当前时间的7段数码管，要求精确到分钟

好的，以下是使用Python的turtle库绘制当前时间的7段数码管的代码，精确到分钟：

import turtle
import time

# 定义数字0-9的7段数码管的线段坐标
digit = [
    [(0, 0), (0, 50), (50, 50), (50, 0), (0, 0)],  # 0
    [(0, 0), (0, 50), (0, 25), (50, 25), (50, 0), (0, 0)],  # 1
    [(0, 0), (50, 0), (50, 25), (0, 25), (0, 50), (50, 50)],  # 2
    [(0, 0), (50, 0), (50, 25), (0, 25), (50, 25), (50, 50), (0, 50)],  # 3
    [(0, 0), (0, 25), (50, 25), (50, 0), (50, 50)],  # 4
    [(50, 0), (0, 0), (0, 25), (50, 25), (50, 50), (0, 50)],  # 5
    [(50, 0), (0, 0), (0, 50), (50, 50), (50, 25), (0, 25)],  # 6
    [(0, 0), (50, 0), (50, 50), (0, 50)],  # 7
    [(0, 0), (0, 50), (50, 50), (50, 25), (0, 25), (50, 25), (50, 0), (0, 0)],  # 8
    [(0, 50), (50, 50), (50, 0), (0, 0), (0, 25), (50, 25)],  # 9
]

# 定义绘制数码管的函数
def draw_digit(d, x, y):
    turtle.penup()
    turtle.goto(x, y)
    turtle.pendown()
    for i in range(len(d)):
        turtle.goto(d[i][0] + x, d[i][1] + y)
    turtle.penup()

# 获取当前时间的小时和分钟
now = time.localtime()
hour = now.tm_hour
minute = now.tm_min

# 绘制小时的十位数
draw_digit(digit[hour // 10], -250, 0)
# 绘制小时的个位数
draw_digit(digit[hour % 10], -150, 0)
# 绘制冒号
draw_digit(digit[10], -50, 0)
# 绘制分钟的十位数
draw_digit(digit[minute // 10], 50, 0)
# 绘制分钟的个位数
draw_digit(digit[minute % 10], 150, 0)

turtle.done()

运行上述代码，可以在窗口中看到当前时间的7段数码管，精确到分钟。