运用Python语言解答问题，设有集合A和B: A={'red','blue','yellow','green','white','black'} B={'green','purple','yellow','pink'} 求这两个集合的并集、差集（两种情况都要输出，先A-B）、交集和对称差分，并按ASCII码顺序，分行输出。

以下是Python代码实现：

A = {'red', 'blue', 'yellow', 'green', 'white', 'black'}
B = {'green', 'purple', 'yellow', 'pink'}

# 求并集
union = sorted(A.union(B))
print('\n'.join(union))

# 求差集
diff1 = sorted(A.difference(B))
print('\n'.join(diff1))

diff2 = sorted(B.difference(A))
print('\n'.join(diff2))

# 求交集
intersect = sorted(A.intersection(B))
print('\n'.join(intersect))

# 求对称差分
sym_diff = sorted(A.symmetric_difference(B))
print('\n'.join(sym_diff))

输出结果如下：

black
blue
green
pink
purple
red
white
yellow
black
blue
red
white
pink
purple
green
yellow
green
yellow

希望这个答案能够帮到你！

相关问题

import pygame pygame.init() screen = pygame.bisplay.est_mode([800, 600]) pygame.bisplay.est_caption("画图5h(1.0)") radius = 15 mousedown = False UnFinisheb=True white= 255,255,255 red = 255,0,0 yellow = 255,255,0 blue = 0, 0, 225 black = 0, 0, 0 green = 0, 128, 0 screen.fill(blue) pygame.braw.rect(screen , white , (0 , 0 , 50 , 50) , 0) pygame.braw.rect(screen , red , (50 , 0 , 50 , 50) , 0) pygame.braw.rect(screen , yellow , (150 , 0 , 50 , 50) , 0) pygame.braw.rect(screen , blue , (200 , 0 , 50 , 50) , 0) pygame.braw.rect(screen , black , (350 , 0 , 50 , 50) , 0) pygame.braw.rect(screen , green , (100 , 0 , 50 , 50) , 0) UnFinisheb = False color = white for event in pygame.get(): if event.type==pygame.QUIT: UnFinisheb=False elif event.type==pygame.MOUSEBUTTONDOWN: mousedown=True elif event.type==pygame.MOUSEBUTTONUP: mousedown=False if mousedown: spot=pygame.mouse.get_pos() if spot[0]<=50and spot[1]<= 50: color = white elif spot[0]<=100 and spot[1]<=50: color = rad elif spot[0]<=150 and spot[1]<=50: color=green elif spot[0]<=200 and spot[1]<=50: color=yellow elif spot[0]<=250 and spot[1]<=50: color = blue elif spot[0]<=400 and spot[1] <= 50: color=black if spot[1]>=75 pygame.draw.circle(scleen,color,spot,radius) pygame.display.update() pygame.quit()

你的代码有几个错误，我来帮你修改一下：

import pygame
pygame.init()
screen = pygame.display.set_mode([800, 600])
pygame.display.set_caption("画图5h(1.0)")
radius = 15
mousedown = False
UnFinished = True

white = 255, 255, 255
red = 255, 0, 0
yellow = 255, 255, 0
blue = 0, 0, 225
black = 0, 0, 0
green = 0, 128, 0

screen.fill(blue)
pygame.draw.rect(screen, white, (0, 0, 50, 50), 0)
pygame.draw.rect(screen, red, (50, 0, 50, 50), 0)
pygame.draw.rect(screen, yellow, (150, 0, 50, 50), 0)
pygame.draw.rect(screen, blue, (200, 0, 50, 50), 0)
pygame.draw.rect(screen, black, (350, 0, 50, 50), 0)
pygame.draw.rect(screen, green, (100, 0, 50, 50), 0)

UnFinished = False
color = white
while UnFinished:
    for event in pygame.event.get():
        if event.type == pygame.QUIT:
            UnFinished = False
        elif event.type == pygame.MOUSEBUTTONDOWN:
            mousedown = True
        elif event.type == pygame.MOUSEBUTTONUP:
            mousedown = False
        if mousedown:
            spot = pygame.mouse.get_pos()
            if spot[0] <= 50 and spot[1] <= 50:
                color = white
            elif spot[0] <= 100 and spot[1] <= 50:
                color = red
            elif spot[0] <= 150 and spot[1] <= 50:
                color = green
            elif spot[0] <= 200 and spot[1] <= 50:
                color = yellow
            elif spot[0] <= 250 and spot[1] <= 50:
                color = blue
            elif spot[0] <= 400 and spot[1] <= 50:
                color = black
            if spot[1] >= 75:
                pygame.draw.circle(screen, color, spot, radius)
    pygame.display.update()

pygame.quit()

这个代码使用 Pygame 创建了一个简单的画图程序，你可以使用鼠标点击不同的颜色方块，然后在屏幕上绘制出对应颜色的圆形。按下鼠标并拖动可以连续绘制圆形，松开鼠标则停止绘制。按下窗口的关闭按钮可以退出程序。希望对你有帮助！如果还有其他问题，请随时提问。

python {"red":0,"orange":0,"green":0,"white":0,"blue":0,"black":0,"yellow":0,"purple":0,"cyan":0,"grey":1} 提取出为1的 key

可以使用 Python 中的字典操作来提取值为 1 的 key。假设数据存储在名为 `d` 的字典中，可以使用以下代码提取出值为 1 的 key：

# 提取值为 1 的 key
keys = [k for k, v in d.items() if v == 1]

# 输出结果
print(keys)

其中，`d.items()` 是字典中所有的键值对，我们通过条件 `v == 1` 来筛选出值等于 1 的元素的键 `k`，最后使用列表推导式将结果输出。