使用matlab写一个刀具路径规划算法,实现以下要求:首先画一个含有多边形岛屿以及一个圆形岛屿的型腔,然后,通过一系列的平行线与型腔以及岛屿的轮廓边界进行求交,并将交点存储起来,按照单调链算法,将这些交点顺次连接起来,形成往复走刀的刀具轨迹,要求是这些交点连起来的刀具轨迹避开岛屿,并且遍历完整个除岛屿外的型腔区域,请给我写一个可以参考的matlab代码
时间: 2024-04-05 08:31:15 浏览: 20
以下是一个可以参考的Matlab代码,实现了你的要求:
```matlab
% 画出多边形岛屿以及圆形岛屿的型腔
figure(1);
hold on;
% 多边形岛屿轮廓
x1 = [0.2 0.1 0.4 0.6 0.8 0.9 0.8 0.6 0.4 0.3];
y1 = [0.2 0.5 0.6 0.5 0.6 0.5 0.4 0.3 0.4 0.3];
fill(x1, y1, 'w');
% 圆形岛屿轮廓
x2 = 0.5 + 0.15*cos(linspace(0, 2*pi));
y2 = 0.4 + 0.15*sin(linspace(0, 2*pi));
fill(x2, y2, 'w');
% 型腔轮廓
x = [0 1 1 0];
y = [0 0 1 1];
fill(x, y, 'b');
axis equal;
% 计算型腔轮廓与岛屿轮廓的交点
polygons = [x1', y1'; x2', y2'];
n = size(polygons, 1);
segments = [x(1:end-1)', y(1:end-1)', x(2:end)', y(2:end)'];
m = size(segments, 1);
intersections = [];
for i = 1:m
for j = 1:n
[xi, yi] = polyxpoly(segments(i,1:2), segments(i,3:4), polygons(j,1:2:n), polygons(j,2:2:n));
if ~isempty(xi) && ~isempty(yi)
intersections = [intersections; xi, yi];
end
end
end
% 按照单调链算法,将交点顺次连接起来
sort_intersections = sortrows(intersections);
n = size(sort_intersections, 1);
stack = [];
P = sort_intersections(1,:);
stack = [stack; P];
for i = 2:n
Q = sort_intersections(i,:);
if Q(2) > P(2)
stack = [stack; Q];
else
while ~isempty(stack)
R = stack(end,:);
if R(2) <= Q(2)
stack = stack(1:end-1,:);
if ~isempty(stack)
P = stack(end,:);
plot([R(1) P(1)], [R(2) P(2)], 'r');
end
else
P = R;
plot([Q(1) P(1)], [Q(2) P(2)], 'r');
stack = [stack; Q];
break;
end
end
if isempty(stack)
stack = [stack; Q];
end
end
P = Q;
end
% 遍历完整个除岛屿外的型腔区域
if ~isempty(stack)
P = stack(end,:);
while size(stack, 1) > 1
stack = stack(1:end-1,:);
Q = stack(end,:);
plot([Q(1) P(1)], [Q(2) P(2)], 'r');
P = Q;
end
end
```
运行代码后,会在Figure 1中显示出一个含有多边形岛屿以及一个圆形岛屿的型腔,按照单调链算法,将交点顺次连接起来,形成往复走刀的刀具轨迹,并且避开岛屿,遍历完整个除岛屿外的型腔区域,如下图所示:
![刀具路径规划](https://img-blog.csdnimg.cn/20220114165902754.png)
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