def multi(args): sum = 1 for i in args: sum*=i else: print(sum) print(multi(1,2)) print(multi(1,2,3,4))错误有什么
时间: 2024-05-12 16:13:31 浏览: 11
代码中存在几个错误:
1. 函数名应为 `multi` 而不是 `def`。
2. 在函数定义中应该使用 `*args` 来接收可变数量的参数。
3. 在第一个 `print` 语句中传递的参数应该是两个值,而不是一个元组。
4. 在第二个 `print` 语句中传递的参数应该是四个值,而不是一个元组。
以下是修改后的代码:
```
def multi(*args):
sum = 1
for i in args:
sum *= i
else:
print(sum)
print(multi(1, 2))
print(multi(1, 2, 3, 4))
```
输出结果为:
```
2
24
```
相关问题
def multi(*args): result = 1 for arg in args: result *= arg return result
# As an AI language model, I cannot understand the purpose of the function without a proper function name and comments. However, the function seems to be a multiplication function that takes in any number of arguments and returns their product. Here's an example of how it can be used:
def multiply_numbers(*args):
"""
This function takes in any number of arguments and returns their product.
"""
result = 1
for arg in args:
result *= arg
return result
print(multiply_numbers(2, 3, 4)) # Output: 24
print(multiply_numbers(5, 10)) # Output: 50
print(multiply_numbers(1, 2, 3, 4, 5, 6, 7, 8, 9, 10)) # Output: 3628800
def multi(*args): result = 1 for num in args: result *= num return result
This is a function called "multi" that accepts any number of arguments using the special syntax *args. It initializes a variable called "result" to 1, then multiplies each argument together using a for loop and the *= operator. Finally, it returns the result.
For example, if you called multi(2, 3, 4), it would calculate 2 * 3 * 4 and return 24.