passing argument 1 of 'search' makes pointer from integer without a cast [-Wint-conversion]
时间: 2024-05-05 21:17:00 浏览: 262
This warning message typically occurs when you are passing an integer value to a function that expects a pointer as its argument. The compiler is warning you that there is a mismatch between the type of the argument you are passing and the type the function expects.
To fix this warning, you should ensure that you are passing the correct type of argument to the function. If the function expects a pointer, you should pass a pointer variable or address. If you are passing an integer value, you may need to cast it to a pointer type before passing it to the function.
For example, consider the following code:
```
int search(int *array, int size, int key) {
// implementation of search function
}
int main() {
int arr[] = {1, 2, 3, 4, 5};
int key = 3;
int index = search(key, arr, 5);
// rest of the code
}
```
Here, we are passing the arguments to the `search` function in the wrong order. The function expects an array pointer as its first argument, but we are passing an integer value (`key`) instead. To fix this, we should swap the order of the arguments:
```
int main() {
int arr[] = {1, 2, 3, 4, 5};
int key = 3;
int index = search(arr, 5, key);
// rest of the code
}
```
If you are still getting the warning message after correcting the argument types, you may need to check the function declaration to ensure that it matches the expected argument types.
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