用java解决问题。 Return the sum of the numbers in the array, except ignore sections of numbers starting with a 6 and extending to the next 7 (every 6 will be followed by at least one 7). Return 0 for no numbers.
时间: 2023-06-25 10:07:55 浏览: 51
可以使用一个标记变量 `foundSix` 来记录是否已经找到了 6,如果找到 6,就将其后的数字累加时忽略,直到找到了 7。
下面是用 Java 实现的代码:
```
public static int sum67(int[] nums) {
boolean foundSix = false;
int sum = 0;
for (int num : nums) {
if (num == 6) {
foundSix = true;
} else if (num == 7 && foundSix) {
foundSix = false;
} else if (!foundSix) {
sum += num;
}
}
return sum;
}
```
我们用 `foundSix` 变量来标记是否已经找到了 6,如果找到了 6,就将 `foundSix` 设为 true。如果找到了 7,并且 `foundSix` 为 true,就将 `foundSix` 设为 false,表示已经找完了这一段需要忽略的数字。如果 `foundSix` 为 false,就将当前数字累加到 `sum` 中。
最后返回 `sum` 即可。
相关问题
i dont want it to ignore the zero in between the numbers of the two columns
If you don't want to ignore the zero in between the numbers of the two columns when merging, you can use the `apply` function along with a lambda function to concatenate the values as strings. Here's an example:
```python
import pandas as pd
# Create an example DataFrame
df = pd.DataFrame({'A': [1, 2, 3], 'B': [4, 5, 6]})
# Merge the two columns with zero in between
df['C'] = df.apply(lambda row: str(row['A']) + '0' + str(row['B']), axis=1)
print(df)
```
Output:
```
A B C
0 1 4 104
1 2 5 205
2 3 6 306
```
In the above code, we use `apply` along with a lambda function to concatenate the values of columns `A` and `B`. We add '0' in between the values to ensure it is included in the merged result. The `axis=1` parameter is used to apply the lambda function row-wise.
Each hospital should have the same number of masks and gowns. Write a C++ program that reads all the data from the file and displays each hospital with the number of items that are needed to make the two numbers the same.
Here's an example program that reads the data from the "equipment.txt" file and displays each hospital with the number of items needed to make the number of masks and gowns the same:
```c++
#include <iostream>
#include <fstream>
#include <sstream>
#include <string>
using namespace std;
int main() {
ifstream file("equipment.txt");
string line;
// Read each line of the file
while (getline(file, line)) {
stringstream ss(line);
string hospital;
int masks, gowns;
// Parse the line into hospital name, number of masks, and number of gowns
getline(ss, hospital, ';');
ss >> masks;
ss.ignore();
ss >> gowns;
// Calculate the number of items needed to make masks and gowns the same
int diff = abs(masks - gowns);
int total = masks + gowns;
int needed = total / 2 - min(masks, gowns);
// Display the results
cout << hospital << ": Needs " << needed << " more of ";
if (masks < gowns) {
cout << "masks\n";
} else {
cout << "gowns\n";
}
}
// Close the file
file.close();
return 0;
}
```
In this program, we first create an object of the `ifstream` class named "file" and pass the name of the file we want to read from as an argument to the constructor.
Then, we read each line of the file using the `getline()` function and parse it into the hospital name, number of masks, and number of gowns using a `stringstream`.
Next, we calculate the number of items needed to make masks and gowns the same by finding the absolute difference between the two and dividing the total by 2, then subtracting the lower number of masks or gowns.
Finally, we display the results by printing the hospital name and the number of items needed to make the two numbers the same, along with whether more masks or gowns are needed.
Note that we use the `abs()` function to ensure that the difference between masks and gowns is always positive, regardless of which number is greater.