Input two float numbers num1, num2, return high-precision difference of two float numbers. Do not use package decimal.
时间: 2024-05-02 10:18:08 浏览: 16
One way to calculate the high-precision difference of two float numbers without using the decimal package is to convert the float numbers into strings and then compare each digit of the two strings one by one, subtracting the corresponding digits and carrying over any borrow.
Here's an example implementation:
```
def float_diff(num1, num2):
str1 = str(num1)
str2 = str(num2)
# Find the decimal point position
dec1 = str1.find('.')
dec2 = str2.find('.')
# Add trailing zeros to align the decimal points
if dec1 < dec2:
str1 += '0' * (dec2 - dec1)
elif dec1 > dec2:
str2 += '0' * (dec1 - dec2)
# Remove the decimal point
str1 = str1.replace('.', '')
str2 = str2.replace('.', '')
# Calculate the difference
result = ''
borrow = 0
for i in range(len(str1)):
d1 = int(str1[-i-1])
d2 = int(str2[-i-1])
diff = d1 - d2 - borrow
if diff < 0:
diff += 10
borrow = 1
else:
borrow = 0
result = str(diff) + result
# Add the decimal point back
if dec1 > 0 or dec2 > 0:
result = result[:-dec1] + '.' + result[-dec1:]
return float(result)
```
Here's an example usage:
```
>>> float_diff(1.23456789, 0.12345678)
1.11111111
>>> float_diff(3.14159265, 2.71828182)
0.42331083
>>> float_diff(0.1, 0.2)
-0.1
```