Python制作吃豆人游戏
时间: 2023-07-09 07:49:29 浏览: 135
好的,下面是一个简单的Python制作吃豆人游戏的步骤:
1. 导入必要的库
```
import pygame
import random
```
2. 初始化pygame
```
pygame.init()
```
3. 定义游戏窗口大小和吃豆人、豆子的初始位置
```
WINDOW_WIDTH = 600
WINDOW_HEIGHT = 600
PACMAN_SIZE = 20
PACMAN_POS = [(WINDOW_WIDTH/2, WINDOW_HEIGHT/2)]
FOOD_SIZE = 10
FOOD_POS = [(random.randint(0, (WINDOW_WIDTH-FOOD_SIZE)//FOOD_SIZE) * FOOD_SIZE, random.randint(0, (WINDOW_HEIGHT-FOOD_SIZE)//FOOD_SIZE) * FOOD_SIZE) for i in range(10)]
```
4. 创建游戏窗口
```
screen = pygame.display.set_mode((WINDOW_WIDTH, WINDOW_HEIGHT))
pygame.display.set_caption('吃豆人')
```
5. 定义吃豆人的移动方向
```
direction = 'right'
```
6. 定义豆子的数量
```
food_count = 10
```
7. 定义游戏循环
```
while True:
# 处理事件
for event in pygame.event.get():
if event.type == pygame.QUIT:
pygame.quit()
sys.exit()
elif event.type == pygame.KEYDOWN:
if event.key == pygame.K_LEFT:
direction = 'left'
elif event.key == pygame.K_RIGHT:
direction = 'right'
elif event.key == pygame.K_UP:
direction = 'up'
elif event.key == pygame.K_DOWN:
direction = 'down'
# 移动吃豆人
if direction == 'left':
PACMAN_POS[0] = (PACMAN_POS[0][0]-PACMAN_SIZE, PACMAN_POS[0][1])
elif direction == 'right':
PACMAN_POS[0] = (PACMAN_POS[0][0]+PACMAN_SIZE, PACMAN_POS[0][1])
elif direction == 'up':
PACMAN_POS[0] = (PACMAN_POS[0][0], PACMAN_POS[0][1]-PACMAN_SIZE)
elif direction == 'down':
PACMAN_POS[0] = (PACMAN_POS[0][0], PACMAN_POS[0][1]+PACMAN_SIZE)
# 判断是否吃到豆子
for i in range(food_count):
if PACMAN_POS[0] == FOOD_POS[i]:
FOOD_POS[i] = (random.randint(0, (WINDOW_WIDTH-FOOD_SIZE)//FOOD_SIZE) * FOOD_SIZE, random.randint(0, (WINDOW_HEIGHT-FOOD_SIZE)//FOOD_SIZE) * FOOD_SIZE)
# 绘制游戏界面
screen.fill((255, 255, 255))
for pos in PACMAN_POS:
pygame.draw.circle(screen, (255, 255, 0), (int(pos[0]+PACMAN_SIZE/2), int(pos[1]+PACMAN_SIZE/2)), int(PACMAN_SIZE/2))
for pos in FOOD_POS:
pygame.draw.circle(screen, (255, 0, 0), (int(pos[0]+FOOD_SIZE/2), int(pos[1]+FOOD_SIZE/2)), int(FOOD_SIZE/2))
pygame.display.update()
```
这就是一个简单的吃豆人游戏的制作过程,可以根据需求进行修改和完善。
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