ListBuffer怎么转成类似["xx","xx"]的形式

可以使用ListBuffer的toList方法和mkString方法来实现：

import scala.collection.mutable.ListBuffer

val listBuffer = ListBuffer("xx", "xx")
val result = listBuffer.toList.mkString("[\"", "\",\"", "\"]")
println(result) // ["xx","xx"]

这里先将ListBuffer转换为List，然后使用mkString方法将List转换为字符串，其中第一个参数是字符串的开头，第二个参数是元素之间的分隔符，第三个参数是字符串的结尾。

相关问题

ListBuffer可以直接转成string类型吗？

ListBuffer不能直接转换为string类型，但可以通过将其转换为List类型，然后使用mkString方法将其转换为string类型。例如：

import scala.collection.mutable.ListBuffer

val listBuffer = ListBuffer(1, 2, 3)
val list = listBuffer.toList
val str = list.mkString(",")
println(str) // "1,2,3"

scala listbuffer

Scala ListBuffer is a mutable sequence data structure that allows you to add, remove, and modify elements in the list. It is similar to an array or a list, but with the added advantage of being mutable.

Here is an example of how to use ListBuffer in Scala:

import scala.collection.mutable.ListBuffer

// create a ListBuffer
val listBuffer = ListBuffer(1, 2, 3)

// add elements to the ListBuffer
listBuffer += 4
listBuffer ++= List(5, 6)

// remove elements from the ListBuffer
listBuffer -= 4
listBuffer.remove(2)

// modify elements in the ListBuffer
listBuffer(1) = 7

// print the ListBuffer
println(listBuffer)

Output:

ListBuffer(1, 7, 5, 6)

As you can see, ListBuffer allows you to add, remove, and modify elements in the list, making it a powerful tool for working with mutable sequences in Scala.