(1)数组a[12]中数据满足以下特点：a[n]=a[n-1]+a[n-2]+1。现在a[0]=-6, a[1]=0，请用c++编程输出数组后边各元素的值。

int a[12];
a[0] = -6;
a[1] = 0;
for (int i = 2; i < 12; i++) {
a[i] = a[i-1] + a[i-2] + 1;
}
for (int i = 0; i < 12; i++) {
printf("a[%d] = %d\n", i, a[i]);
}