fruits = {"apple":10,"mango":12,"durian":20,"banana":5} m = 'apple' for key in fruits.keys(): print('{}:{}'.format(m,fruits[m]))用字典的方式输出最大值
时间: 2023-06-17 12:06:32 浏览: 316
你可以使用字典的内置方法`max()`来找到字典中值最大的键,然后使用该键来打印对应的键值对。下面是代码实现:
```
fruits = {"apple":10,"mango":12,"durian":20,"banana":5}
max_key = max(fruits, key=fruits.get) # 找到值最大的键
print('{}:{}'.format(max_key, fruits[max_key])) # 打印对应的键值对
```
输出结果为:
```
durian:20
```
相关问题
fruits={"apple":10,"mango":12,"durian":20,"banana":5}输出最大键值对
以下是根据提供的引用内容给出的回答:
```python
fruits = {"apple":10, "mango":12, "durian":20, "banana":5}
m = "apple"
for key in fruits.keys():
if fruits[m] < fruits[key]:
m = key
print("最大键值的键值对为{}:{}".format(m, fruits[m]))
```
输出结果为:最大键值的键值对为durian:20
fruits = {"apple":10,"mango":12,"durian":20,"banana":5} m = 'apple' for key in fruits.keys(): print('{}:{}'.format(m,fruits[m]))完善代码,输出最大值
fruits = {"apple":10,"mango":12,"durian":20,"banana":5}
m = 'apple'
max_fruit = max(fruits, key=fruits.get)
for key in fruits.keys():
print('{}:{}'.format(m,fruits[m]))
print("Max value: {} - {}".format(max_fruit, fruits[max_fruit]))