R语言中同时用Logistic生长模型、Richards生长模型、Gompertz生长模型去拟合14个值时,怎么使它们同时好看的出现在一幅图上代码
时间: 2024-05-13 20:16:18 浏览: 92
可以使用ggplot2包来绘制图形。以下是一个示例代码,其中使用了三种生长模型来拟合14个值,并将它们同时绘制在一张图中:
```R
library(ggplot2)
# 构造数据
x <- 1:14
y <- c(0.2, 0.5, 0.8, 1.5, 2.3, 3.0, 3.5, 3.8, 4.0, 4.2, 4.5, 4.7, 4.9, 5.0)
# 定义三种生长模型
logistic <- function(x, a, b, c) {
c + (a - c) / (1 + exp(-b * (x - c)))
}
richards <- function(x, a, b, c, d) {
a + (b - a) / (1 + exp(-c * (x - d)))
}
gompertz <- function(x, a, b, c) {
a * exp(-b * exp(-c * x))
}
# 拟合数据
fit_logistic <- nls(y ~ logistic(x, a, b, c), start = list(a = 5, b = 1, c = 7))
fit_richards <- nls(y ~ richards(x, a, b, c, d), start = list(a = 1, b = 5, c = 1, d = 7))
fit_gompertz <- nls(y ~ gompertz(x, a, b, c), start = list(a = 5, b = 1, c = 0.1))
# 绘制图形
ggplot(data.frame(x = x, y = y), aes(x = x, y = y)) +
geom_point() +
geom_smooth(method = "nls", formula = y ~ logistic(x, a, b, c), se = FALSE, method.args = list(start = coef(fit_logistic)), color = "red") +
geom_smooth(method = "nls", formula = y ~ richards(x, a, b, c, d), se = FALSE, method.args = list(start = coef(fit_richards)), color = "blue") +
geom_smooth(method = "nls", formula = y ~ gompertz(x, a, b, c), se = FALSE, method.args = list(start = coef(fit_gompertz)), color = "green") +
labs(title = "三种生长模型拟合数据", x = "x", y = "y") +
theme_bw()
```
在上面的代码中,首先加载ggplot2包并定义了三个生长模型:logistic、richards和gompertz。然后使用nls函数拟合数据,分别得出fit_logistic、fit_richards和fit_gompertz三个模型的系数。最后使用ggplot2来绘制图形,其中geom_point绘制原始数据点,geom_smooth绘制拟合曲线,并使用不同的颜色区分三个生长模型。通过设置标题和坐标轴标签,使图形更加清晰易懂。
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