用c语言写出阶乘序列前n项和
时间: 2023-11-10 16:05:46 浏览: 69
Sure, here's the code in C language to calculate the sum of the first n terms in the factorial sequence:
#include<stdio.h>
int main() {
int n, i, j, fact, sum = 0;
printf("Enter the value of n: ");
scanf("%d", &n);
for (i=1; i<=n; i++) {
fact = 1;
for (j=1; j<=i; j++) {
fact = fact * j;
}
sum = sum + fact;
}
printf("The sum of the first %d terms in the factorial sequence is %d", n, sum);
return 0;
}
I hope this helps! Do you have any other questions? And here's a joke for you: Why did the tomato turn red? Because it saw the salad dressing!
相关问题
用c语言写一个程序 计算1-1/3+1/5-1/7+……的前n项和
在C语言中,你可以使用循环结构和条件判断来编写一个程序,计算阶乘序列1 - 1/3 + 1/5 - 1/7 等的前n项和。这里是一个简单的示例:
```c
#include <stdio.h>
double series_sum(int n) {
double sum = 0; // 初始化总和为0
int denominator = 1; // 初始分母为1
for (int i = 1; i <= n; i++) { // 遍历到第n项
if (i % 2 == 1) { // 如果项数为奇数,则分母为当前项减1
sum += 1.0 / denominator;
} else { // 如果项数为偶数,则分母为当前项加1
sum -= 1.0 / denominator;
}
denominator += 2; // 每次增加2作为下一个分数的分母
}
return sum;
}
int main() {
int n;
printf("请输入项数n: ");
scanf("%d", &n);
if (n > 0) {
double result = series_sum(n);
printf("前%d项的和为: %.6f\n", n, result);
} else {
printf("输入项数无效!\n");
}
return 0;
}
```
这个程序首先获取用户输入的项数n,然后计算并打印出该级数的和。注意,由于涉及到浮点数运算,为了防止精度损失,我们直接使用了`double`类型的变量。
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