要求栈显示如下功能:\n1.入栈\n2.出栈\n3.查看栈顶元素\n4.查看栈长度\n5.查看栈中元素\n6.退出

这是一个二进制字符串，需要先将其转换为可读的文本。转换后为：

要求栈显示如下功能：
1.入栈
2.出栈
3.查看栈顶元素
4.查看栈长度
5.查看栈中元素
6.退出

答案：
这是一个栈数据结构的基本功能需求，包括入栈、出栈、查看栈顶元素、查看栈长度、查看栈中元素以及退出。

相关问题

创建顺序栈的结构、出栈、入栈、取栈顶元素算法： 2.创建判断表达式括号匹配、判断运算符、运算符优先级和两数运算的函数：

1. 创建顺序栈的结构、出栈、入栈、取栈顶元素算法：

class Stack:
    def __init__(self):
        self.stack = []

    def push(self, item):
        self.stack.append(item)

    def pop(self):
        return self.stack.pop()

    def peek(self):
        return self.stack[-1]

    def is_empty(self):
        return len(self.stack) == 0

其中，`push` 方法用于入栈，`pop` 方法用于出栈，`peek` 方法用于取栈顶元素，`is_empty` 方法用于判断栈是否为空。

2. 创建判断表达式括号匹配、判断运算符、运算符优先级和两数运算的函数：

def is_matching_parentheses(expr):
    stack = Stack()
    for char in expr:
        if char in '({[':
            stack.push(char)
        elif char in ')}]':
            if stack.is_empty():
                return False
            elif char == ')' and stack.peek() == '(':
                stack.pop()
            elif char == '}' and stack.peek() == '{':
                stack.pop()
            elif char == ']' and stack.peek() == '[':
                stack.pop()
            else:
                return False
    return stack.is_empty()


def is_operator(char):
    return char in '+-*/'


def get_operator_precedence(char):
    if char in '+-':
        return 1
    elif char in '*/':
        return 2
    else:
        return -1


def evaluate(expr):
    operand_stack = Stack()
    operator_stack = Stack()
    i = 0
    while i < len(expr):
        if expr[i].isdigit():
            j = i
            while j < len(expr) and expr[j].isdigit():
                j += 1
            operand = int(expr[i:j])
            operand_stack.push(operand)
            i = j
        elif is_operator(expr[i]):
            while not operator_stack.is_empty() and get_operator_precedence(operator_stack.peek()) >= get_operator_precedence(expr[i]):
                operator = operator_stack.pop()
                operand2 = operand_stack.pop()
                operand1 = operand_stack.pop()
                result = evaluate_operation(operand1, operand2, operator)
                operand_stack.push(result)
            operator_stack.push(expr[i])
            i += 1
        else:
            i += 1
    while not operator_stack.is_empty():
        operator = operator_stack.pop()
        operand2 = operand_stack.pop()
        operand1 = operand_stack.pop()
        result = evaluate_operation(operand1, operand2, operator)
        operand_stack.push(result)
    return operand_stack.pop()


def evaluate_operation(operand1, operand2, operator):
    if operator == '+':
        return operand1 + operand2
    elif operator == '-':
        return operand1 - operand2
    elif operator == '*':
        return operand1 * operand2
    elif operator == '/':
        return operand1 / operand2
    else:
        raise ValueError('Unknown operator: ' + operator)

其中，`is_matching_parentheses` 函数用于判断表达式中的括号是否匹配，`is_operator` 函数用于判断一个字符是否为运算符，`get_operator_precedence` 函数用于获取一个运算符的优先级，`evaluate` 函数用于计算表达式的值，`evaluate_operation` 函数用于对两个操作数进行指定的运算。

用Python创建顺序栈的结构、出栈、入栈、取栈顶元素算法： 2. 创建判断表达式括号匹配、判断运算符、运算符优先级和两数运算的函数： 3.实现中缀表达式求值算法：

1. 创建顺序栈的结构、出栈、入栈、取栈顶元素算法:

顺序栈可以使用Python中的列表来实现。定义一个空列表来表示空栈，使用append()方法实现入栈操作，使用pop()方法实现出栈操作并返回被移除元素。使用[-1]索引来取栈顶元素。

以下是示例代码：

class Stack():
    def __init__(self):
        self.items = []
        
    def is_empty(self):
        return self.items == []
    
    def push(self, item):
        self.items.append(item)
        
    def pop(self):
        return self.items.pop()
    
    def peek(self):
        return self.items[-1]

2. 创建判断表达式括号匹配、判断运算符、运算符优先级和两数运算的函数：

可以使用栈来实现表达式求值。先将操作数压入栈中，当遇到运算符时，取出相应的操作数按照运算符计算，将结果再次压入栈中。最后栈中剩余的操作数即为最终结果。

以下是示例代码：

def is_operator(c):
    return c in ['+', '-', '*', '/']

def operator_priority(operator):
    return {'+': 1, '-': 1, '*': 2, '/': 2}[operator]

def calculate(num1, num2, operator):
    if operator == '+':
        return num1 + num2
    elif operator == '-':
        return num1 - num2
    elif operator == '*':
        return num1 * num2
    elif operator == '/':
        return num1 / num2
    
def evaluate_expression(expression):
    stack_num = []
    stack_operator = []
    
    for c in expression:
        if c.isdigit():
            stack_num.append(int(c))
        elif is_operator(c):
            while stack_operator and operator_priority(stack_operator[-1]) >= operator_priority(c):
                num2 = stack_num.pop()
                num1 = stack_num.pop()
                operator = stack_operator.pop()
                result = calculate(num1, num2, operator)
                stack_num.append(result)
            stack_operator.append(c)
        elif c == '(':
            stack_operator.append(c)
        elif c == ')':
            while stack_operator and stack_operator[-1] != '(':
                num2 = stack_num.pop()
                num1 = stack_num.pop()
                operator = stack_operator.pop()
                result = calculate(num1, num2, operator)
                stack_num.append(result)
            stack_operator.pop()
    
    while stack_operator:
        num2 = stack_num.pop()
        num1 = stack_num.pop()
        operator = stack_operator.pop()
        result = calculate(num1, num2, operator)
        stack_num.append(result)
        
    return stack_num[0]

3. 实现中缀表达式求值算法：

实现中缀表达式求值算法的思路与上述样例类似。在算法中，需要将中缀表达式转为后缀表达式，在后缀表达式中进行求值。

以下是示例代码：

def infix_to_postfix(expression):
    stack_operator = []
    postfix = []
    
    for c in expression:
        if c.isdigit():
            postfix.append(c)
        elif is_operator(c):
            while stack_operator and stack_operator[-1] != '(' and operator_priority(stack_operator[-1]) >= operator_priority(c):
                postfix.append(stack_operator.pop())
            stack_operator.append(c)
        elif c == '(':
            stack_operator.append(c)
        elif c == ')':
            while stack_operator and stack_operator[-1] != '(':
                postfix.append(stack_operator.pop())
            stack_operator.pop()
    
    while stack_operator:
        postfix.append(stack_operator.pop())
        
    return postfix

def evaluate_infix_expression(expression):
    postfix = infix_to_postfix(expression)
    stack = []
    
    for c in postfix:
        if c.isdigit():
            stack.append(int(c))
        elif is_operator(c):
            num2 = stack.pop()
            num1 = stack.pop()
            result = calculate(num1, num2, c)
            stack.append(result)
    
    return stack[0]