用C 代码实现在有13个单词从小到大存入二维字符数组，用折半法找出单词特定单词

的下标位置。

好的，我明白了。以下是实现该功能的C代码：

#include <stdio.h>
#include <string.h>

#define MAX_WORDS 13
#define MAX_WORD_LEN 20

int binarySearch(char words[][MAX_WORD_LEN], int start, int end, char* target) {
    while (start <= end) {
        int mid = start + (end - start) / 2;
        int cmp = strcmp(words[mid], target);
        if (cmp == 0) {
            return mid;
        } else if (cmp < 0) {
            start = mid + 1;
        } else {
            end = mid - 1;
        }
    }
    return -1;
}

int main() {
    char words[MAX_WORDS][MAX_WORD_LEN] = {"apple", "banana", "cat", "dog", "elephant", "fox", "grape", "hello", "ice", "jelly", "kite", "lion", "monkey"};

    // sort the words in ascending order
    for (int i = 0; i < MAX_WORDS - 1; i++) {
        for (int j = i + 1; j < MAX_WORDS; j++) {
            if (strcmp(words[i], words[j]) > 0) {
                char temp[MAX_WORD_LEN];
                strcpy(temp, words[i]);
                strcpy(words[i], words[j]);
                strcpy(words[j], temp);
            }
        }
    }

    // binary search for a target word "elephant"
    char* target = "elephant";
    int index = binarySearch(words, 0, MAX_WORDS - 1, target);
    if (index >= 0) {
        printf("The index of \"%s\" is %d\n", target, index);
    } else {
        printf("Target word \"%s\" not found\n", target);
    }

    return 0;
}

运行该程序会输出：

The index of "elephant" is 4

说明在存有13个单词的二维字符数组中，单词"elephant"的下标位置为4。