首页zip TypeError: 'float' object is not iterable

zip TypeError: 'float' object is not iterable

时间: 2023-10-16 09:08:50 浏览: 179

bare-objects:Object.create(null) 通过节点模块钩子的速记符号

裸对象 Object.create(null) 通过节点模块钩子的速记符号裸对象安装一个 Node 加载器钩子，它转换每个加载的 JavaScript 文件并将<>语法扩展为Object.create(null) var foo = < > ; foo.bar = 'bar'; // use just like normal objects 因为裸对象不继承自 Object，所以没有像 { } + { } // NaN var foo = < > ; foo + foo // TypeError: Cannot convert object to primitive value 为什么？小字作者：Gleb Bahmutov :copyright: 2014 许可证： - 对代码做任何事情，但如果它不起作用，请不要怪我。支持：如果您发现此模块有任何问题，请在 Github 上发

This error occurs when you try to iterate over a float number using the zip function. The zip function is used to combine two or more iterables into a single iterable object. For example, consider the following code: ``` a = [1, 2, 3] b = 4.5 c = [6, 7, 8] zipped = zip(a, b, c) ``` In this code, we are trying to zip three iterables - a list, a float, and another list. However, since a float is not iterable, Python raises a TypeError. To fix this error, you need to make sure that all the objects you pass to the zip function are iterable. In the above example, you can convert the float to a list or a tuple before passing it to the zip function: ``` a = [1, 2, 3] b = [4.5] c = [6, 7, 8] zipped = zip(a, b, c) ``` Here, we have converted the float to a list containing a single element. Now, the zip function can combine all three iterables without any errors.

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