python井字棋小游戏代码不要pygame

当然，我可以帮你概述一个简单的Python井字棋（Tic Tac Toe）游戏代码的基本结构，不使用pygame库。我们将用基本的控制台界面和内置函数来实现。首先，我们需要定义一个`Board`类，用于存储棋盘状态和进行操作。这里是一个简化版的实现：

class Board:
    def __init__(self):
        self.board = [' ' for _ in range(9)]
        self.current_player = 'X'

    def print_board(self):
        for i in range(3):
            print(self.board[i*3:i*3+3])

    def make_move(self, row, col):
        if self.board[row*3 + col] == ' ':
            self.board[row*3 + col] = self.current_player
            self.current_player = 'O' if self.current_player == 'X' else 'X'
        else:
            print("Position is already taken.")

    def check_win(self):
        # 检查行、列和两个对角线是否有一方获胜
        for i in range(9):
            if self.board[i:i+3] == ['X'] * 3 or self.board[i::3] == ['X'] * 3:
                return True
        if self.board[0:3] == ['X'] * 3 or self.board[3:6] == ['X'] * 3 or self.board[6:9] == ['X'] * 3:
            return True
        if self.board == 'X' and self.board == 'X' and self.board == 'X':
            return True
        if self.board == 'X' and self.board == 'X' and self.board == 'X':
            return True
        return False

# 游戏主循环
def play_tictactoe():
    board = Board()
    while not board.check_win():
        board.print_board()
        row = int(input("Player X, enter row (1-3): "))
        col = int(input("Player X, enter column (1-3): "))
        board.make_move(row - 1, col - 1)
        if board.check_win():
            break
    if board.check_win():
        print(f"Player {board.current_player} wins!")
    else:
        print("It's a tie!")

play_tictactoe()