python用pygame井字棋源代码

以下是一个简单的井字棋游戏的 Python 代码，使用 Pygame 模块实现：

import pygame, sys
from pygame.locals import *

# 初始化 Pygame
pygame.init()

# 设置窗口大小和标题
WINDOW_SIZE = (500, 500)
screen = pygame.display.set_mode(WINDOW_SIZE)
pygame.display.set_caption('Tic Tac Toe')

# 设置颜色
BLACK = (0, 0, 0)
WHITE = (255, 255, 255)

# 设置字体
font = pygame.font.Font(None, 36)

# 游戏变量
board = [[0, 0, 0],
         [0, 0, 0],
         [0, 0, 0]]
player = 1
game_over = False
winner = None

# 绘制棋盘
def draw_board():
    for i in range(1, 3):
        pygame.draw.line(screen, BLACK, (i * 150, 0), (i * 150, 450), 5)
        pygame.draw.line(screen, BLACK, (0, i * 150), (450, i * 150), 5)

# 绘制棋子
def draw_piece(row, col):
    x = col * 150 + 75
    y = row * 150 + 75
    if player == 1:
        pygame.draw.circle(screen, WHITE, (x, y), 60, 10)
    else:
        pygame.draw.line(screen, WHITE, (x - 60, y - 60), (x + 60, y + 60), 10)
        pygame.draw.line(screen, WHITE, (x + 60, y - 60), (x - 60, y + 60), 10)

# 检查是否有胜者
def check_winner():
    global game_over, winner
    for i in range(3):
        if board[i][0] == board[i][1] == board[i][2] != 0:
            game_over = True
            winner = board[i][0]
        if board[0][i] == board[1][i] == board[2][i] != 0:
            game_over = True
            winner = board[0][i]
    if board[0][0] == board[1][1] == board[2][2] != 0:
        game_over = True
        winner = board[0][0]
    if board[0][2] == board[1][1] == board[2][0] != 0:
        game_over = True
        winner = board[0][2]
    if all(all(row) for row in board) and not game_over:
        game_over = True

# 显示游戏结果
def show_result():
    if winner:
        text = 'Player {} wins!'.format(winner)
    else:
        text = 'It is a tie!'
    result = font.render(text, True, WHITE, BLACK)
    result_rect = result.get_rect(center=(225, 225))
    screen.blit(result, result_rect)

# 主循环
while True:
    for event in pygame.event.get():
        if event.type == QUIT:
            pygame.quit()
            sys.exit()
        elif event.type == MOUSEBUTTONDOWN and not game_over:
            row = int(event.pos[1] / 150)
            col = int(event.pos[0] / 150)
            if board[row][col] == 0:
                board[row][col] = player
                draw_piece(row, col)
                check_winner()
                if not game_over:
                    player = 3 - player
        elif event.type == KEYDOWN:
            if event.key == K_ESCAPE:
                pygame.quit()
                sys.exit()

    # 清空画布
    screen.fill(BLACK)

    # 绘制棋盘和棋子
    draw_board()
    for row in range(3):
        for col in range(3):
            if board[row][col] != 0:
                draw_piece(row, col)

    # 显示游戏结果
    if game_over:
        show_result()

    # 更新画面
    pygame.display.update()

希望这个代码能够帮助到你！