使用Pygame实现井字棋

好的，我理解了你的要求，我可以给你分享一下使用 Pygame 实现井字棋的代码。

import pygame

pygame.init()

# 设置游戏窗口
WINDOW_SIZE = (300, 300)
screen = pygame.display.set_mode(WINDOW_SIZE)
pygame.display.set_caption("Tic Tac Toe")

# 定义颜色
BLACK = (0, 0, 0)
WHITE = (255, 255, 255)
RED = (255, 0, 0)

# 定义游戏状态
game_over = False
winner = None

# 创建游戏区域
board = [[None] * 3, [None] * 3, [None] * 3]

# 设置字体
font = pygame.font.SysFont(None, 30)

# 绘制游戏区域
def draw_board():
    for row in range(3):
        for col in range(3):
            pygame.draw.rect(screen, WHITE, [(col * 100) + 10, (row * 100) + 10, 80, 80])
            if board[row][col] == "X":
                text = font.render("X", True, BLACK)
                screen.blit(text, ((col * 100) + 35, (row * 100) + 35))
            elif board[row][col] == "O":
                text = font.render("O", True, BLACK)
                screen.blit(text, ((col * 100) + 35, (row * 100) + 35))

# 检查游戏是否结束
def check_game_over():
    global game_over, winner
    # 检查行
    for row in range(3):
        if board[row][0] == board[row][1] == board[row][2] and board[row][0] is not None:
            winner = board[row][0]
            game_over = True
    # 检查列
    for col in range(3):
        if board[0][col] == board[1][col] == board[2][col] and board[0][col] is not None:
            winner = board[0][col]
            game_over = True
    # 检查对角线
    if board[0][0] == board[1][1] == board[2][2] and board[0][0] is not None:
        winner = board[0][0]
        game_over = True
    if board[0][2] == board[1][1] == board[2][0] and board[0][2] is not None:
        winner = board[0][2]
        game_over = True
    # 检查是否平局
    if all([all(row) for row in board]) and winner is None:
        game_over = True

# 主循环
while not game_over:
    for event in pygame.event.get():
        if event.type == pygame.QUIT:
            game_over = True
        if winner is None:
            if event.type == pygame.MOUSEBUTTONDOWN:
                # 获取鼠标点击位置
                xpos, ypos = pygame.mouse.get_pos()
                row = ypos // 100
                col = xpos // 100
                # 检查是否为合法位置
                if board[row][col] is None:
                    # 设置该位置为当前玩家的符号
                    board[row][col] = "X"
                    # 切换到另一个玩家
                    if winner is None:
                        draw_board()
                        check_game_over()
                        pygame.display.update()
                        pygame.time.wait(500)
                        if winner is None:
                            open_spots = [(r, c) for r in range(3) for c in range(3) if board[r][c] is None]
                            if len(open_spots) > 0:
                                row, col = open_spots[0]
                                board[row][col] = "O"
        draw_board()

    pygame.display.update()

# 显示胜者
if winner == "X":
    text = font.render("You win!", True, RED)
elif winner == "O":
    text = font.render("Computer wins!", True, RED)
else:
    text = font.render("Tie game!", True, RED)
screen.blit(text, (80, 140))
pygame.display.update()

# 等待用户关闭窗口
while True:
    for event in pygame.event.get():
        if event.type == pygame.QUIT:
            pygame.quit()
            sys.exit()

希望这个代码对你有帮助！