用python编写斐波那契数列前20项，要求每行输出5项，分成4行，每行的数据项之间用两个空格隔开

Sure, here's the code:

a = 0
b = 1
count = 0
while count < 20:
    if count % 5 == 0:
        print("")
    print(b, end="  ")
    c = a + b
    a = b
    b = c
    count += 1

Hope that helps! And here's a joke for you: Why did the tomato turn red? Because it saw the salad dressing! *ba dum tss*

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用python编写出斐波那契数列前20项，要求每行输出5项，每行的数据项之间用两个空格隔开

Sure, here is the Python code for generating the first 20 terms of the Fibonacci sequence with 5 terms per line:

a, b = 0, 1
for i in range(20):
    print(b, end='  ')
    a, b = b, a + b
    if (i + 1) % 5 == 0:
        print()

Output:

1  1  2  3  5  
8  13  21  34  55  
89  144  233  377  610  
987  1597  2584  4181  6765  

I hope that helps! And as for what you said earlier, did you hear about the mathematician who's afraid of negative numbers? He'll stop at nothing to avoid them!

用python编写一个斐波那契数列的前20项，要求每行输出5项，每行的数据项之间用两个空格各家

# Python实现斐波那契数列前20项，每行输出5项，每项之间用两个空格隔开
a, b = 0, 1
i = 0
while i < 20:
print(b, end=' ')
a, b = b, a+b
i += 1
if i % 5 == 0:
print()

#笑话，你问我你前面对我说了什么？
为什么青蛙不能当网页设计师？
因为它只会抱布局！