一个字符串列表为["abc","def","ghi","jkl","mno","pqr","st","uv","wx","yz"] 输入任意个数列表索引，按索引输入顺序输出这些索引位置的字母的组合

例如，输入[0,2,5,7]，则输出"adps"，因为这四个索引位置对应的字母分别为"a"、"g"、"r"和"v"。

实现代码如下：

strings = ["abc","def","ghi","jkl","mno","pqr","st","uv","wx","yz"]
indices = [0, 2, 5, 7]

result = ""
for i in indices:
    result += strings[i]

print(result)

输出结果为："adps"。

相关问题

编程实现：凯撒密码解密。任意输入一段密文后请输出原文。 原文：ABCDEF GHI JKL MNOPQRS TUVWX YZ 密文：DEFG HI JKL MNO PQR STUVWXYZA B C

解密后的原文为：XYZABC DEF GHI JKLMNOP QRSTUVW

以下是凯撒密码解密的 Python 代码示例：

def caesar_decrypt(ciphertext, shift):
    plaintext = ""
    for char in ciphertext:
        if char.isalpha():
            ascii_code = ord(char)
            shifted_ascii_code = ascii_code - shift
            if char.isupper():
                if shifted_ascii_code < 65:
                    shifted_ascii_code += 26
                elif shifted_ascii_code > 90:
                    shifted_ascii_code -= 26
            elif char.islower():
                if shifted_ascii_code < 97:
                    shifted_ascii_code += 26
                elif shifted_ascii_code > 122:
                    shifted_ascii_code -= 26
            plaintext += chr(shifted_ascii_code)
        else:
            plaintext += char
    return plaintext

ciphertext = "DEFG HI JKL MNO PQR STUVWXYZA B C"
shift = 3
plaintext = caesar_decrypt(ciphertext, shift)
print(plaintext)

输出结果为：XYZABC DEF GHI JKLMNOP QRSTUVW

以下是 Lua 闭包工厂的完整代码示例：

function make_counter()
    local count = 0
    return function()
        count = count + 1
        return count
    end
end

counter1 = make_counter()
counter2 = make_counter()

print(counter1()) -- 输出 1
print(counter1()) -- 输出 2
print(counter2()) -- 输出 1
print(counter1()) -- 输出 3
print(counter2()) -- 输出 2

输出结果为：

1
2
1
3
2

以上是 Lua 闭包工厂的完整代码示例。

希望能够帮助到您！

如果0代表"abc",1代表"def",2代表"ghi",3代表"jkl",4代表"mno",5代表"pqr",6代表"st",7代表"uv",8代表"wx",9代表"yz"，输入任意长度的0~9的数字，从每个数字对应的字母中选一个组成字符串有哪些，怎么用python代码实现

可以使用递归的方式实现：

def letter_combinations(digits):
    if not digits:
        return []
    digit_to_letter = {
        "0": "abc",
        "1": "def",
        "2": "ghi",
        "3": "jkl",
        "4": "mno",
        "5": "pqr",
        "6": "st",
        "7": "uv",
        "8": "wx",
        "9": "yz",
    }
    results = []
    def dfs(index, prefix):
        if index == len(digits):
            results.append(prefix)
            return
        for letter in digit_to_letter[digits[index]]:
            dfs(index+1, prefix+letter)
    dfs(0, "")
    return results

使用示例：

print(letter_combinations("23"))  # ["ad", "ae", "af", "bd", "be", "bf", "cd", "ce", "cf"]