int a = 1; int *b; b = &a; b++;

& a;

This code declares an integer variable `a` and initializes it to 1. Then it declares a pointer variable `b` that is capable of holding the memory address of an integer variable.

The line `b = &a;` assigns the memory address of variable `a` to the pointer variable `b`. So now `b` points to the memory location where the value of `a` is stored.

In other words, `*b` would access the value stored at the memory location pointed to by `b`, which is the value of `a`.

Overall, this code sets up a way to indirectly access the value of `a` through the pointer variable `b`.

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int a=1; int *b; b = &a; b++; b--; 有错误吗

& a;

This code declares an integer variable `a` and initializes it to 1. It then declares a pointer variable `b`, which is assigned the address of `a` using the `&` operator. This means that `b` now points to the memory location where `a` is stored.

Note that the line of code is incomplete as it does not specify what `b` is being assigned to. The code should be completed as follows:

int a = 1; 
int *b; 
b = &a;

Now `b` points to `a` and can be used to access or modify its value indirectly. For example, the following code sets `a` to 2 by dereferencing the pointer `b`:

*b = 2;

After this code is executed, `a` will have the value 2.

int a=1; int *b; b = &a; b++; b--;

& a;

This code declares an integer variable 'a' with value 1 and a pointer variable 'b'. The pointer 'b' is then assigned the memory address of variable 'a' using the address-of operator '&'.

So, 'b' now points to the memory location where 'a' is stored. This means that any changes made to the value of 'a' through 'b' will also reflect in the value of 'a'.

Overall, the code creates an indirect way of accessing and modifying the value of 'a' through the pointer variable 'b'.