判断两个矩阵相等ptaC语言

可以使用循环逐个比较两个矩阵的每一个元素是否相等，如果存在不相等的元素则判断矩阵不相等，否则判断矩阵相等。以下是一个示例代码：

#include <stdio.h>
#include <stdbool.h>

#define ROWS 3
#define COLS 3

bool matrixEqual(int mat1[ROWS][COLS], int mat2[ROWS][COLS]) {
    for (int i = 0; i < ROWS; i++) {
        for (int j = 0; j < COLS; j++) {
            if (mat1[i][j] != mat2[i][j]) {
                return false;
            }
        }
    }
    return true;
}

int main() {
    int mat1[ROWS][COLS] = {{1, 2, 3}, {4, 5, 6}, {7, 8, 9}};
    int mat2[ROWS][COLS] = {{1, 2, 3}, {4, 5, 6}, {7, 8, 9}};
    int mat3[ROWS][COLS] = {{1, 2, 3}, {4, 5, 6}, {9, 8, 7}};

    if (matrixEqual(mat1, mat2)) {
        printf("mat1 and mat2 are equal.\n");
    } else {
        printf("mat1 and mat2 are not equal.\n");
    }

    if (matrixEqual(mat1, mat3)) {
        printf("mat1 and mat3 are equal.\n");
    } else {
        printf("mat1 and mat3 are not equal.\n");
    }

    return 0;
}

输出结果为：

mat1 and mat2 are equal.
mat1 and mat3 are not equal.