#include<stdio.h> #include<stdlib.h> #define maxsize 50 typedef struct { char name[maxsize]; int score; int rank; }student; student* initStu(student *s,int num) { s = (student*)malloc((sizeof(student)) * num); return s; } int main() { student* std; initStu(std, 8); std[0] = {"a",81}; std[1] = { "b",88 }; std[2] = { "c",66 }; std[3] = { "d",25 }; std[4] = { "f",31 }; std[5] = { "g",91 }; std[6] = { "h",61 }; std[7] = { "i",77 }; for (int i = 0; i < 8; i++) { } return 0; }为什么无法运行
时间: 2024-03-25 17:36:11 浏览: 61
#include<stdio.h>
这段代码无法运行的原因是 initStu 函数中的指针 s 没有被正确地初始化。在 main 函数中调用 initStu 函数时,应该将返回值赋值给指针变量 std,如下所示:
```c
int main() {
student* std;
std = initStu(std, 8);
// ... 省略其他代码
}
```
另外,在为结构体数组赋值时,应该使用结构体成员初始化的方式,如下所示:
```c
std[0] = {"a",81,0}; // 注意:需要为 rank 成员赋初值
std[1] = { "b",88,0 };
// ... 省略其他赋值操作
```
最后,需要注意的是,在使用完动态分配的内存后,应该及时释放,以免造成内存泄漏。在这个例子中,可以在 main 函数中添加以下代码来释放内存:
```c
free(std);
```
完整的代码如下所示:
```c
#include <stdio.h>
#include <stdlib.h>
#define maxsize 50
typedef struct {
char name[maxsize];
int score;
int rank;
} student;
student* initStu(student* s, int num) {
s = (student*)malloc(sizeof(student) * num);
return s;
}
int main() {
student* std;
std = initStu(std, 8);
std[0] = {"a",81,0};
std[1] = { "b",88,0 };
std[2] = { "c",66,0 };
std[3] = { "d",25,0 };
std[4] = { "f",31,0 };
std[5] = { "g",91,0 };
std[6] = { "h",61,0 };
std[7] = { "i",77,0 };
for (int i = 0; i < 8; i++) {
printf("Name: %s, Score: %d, Rank: %d\n", std[i].name, std[i].score, std[i].rank);
}
free(std);
return 0;
}
```
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