File "test.py", line 20 print('{:.6f}'.format(sum)) ^ SyntaxError: EOF while scanning triple-quoted string literal
时间: 2024-02-14 07:06:07 浏览: 23
这个错误提示表明在一个三引号字符串中缺少了结束引号,导致解释器在文件结尾处无法正确解析代码。可以检查一下代码中是否有三引号字符串没有正确结束,可以在该行的前面和后面检查一下是否有多余或者缺少的引号。
另外,这个错误提示的行号指向的是解释器最后一次扫描到的三引号字符串,实际上可能在之前的代码中出现了问题,需要仔细检查代码。
相关问题
SyntaxError: EOF while scanning triple-quoted string literal
This error occurs when Python reaches the end of a file or code block while it is still parsing a triple-quoted string literal. This means that there is an unclosed triple-quoted string in your code.
To fix this error, you need to check your code for any triple-quoted strings that are not properly closed. Make sure that all triple-quoted strings have a matching set of three quotes at the beginning and end of the string.
Here's an example of code that would trigger this error:
```
my_string = '''
this is a triple-quoted string
but it doesn't have a closing quote
```
To fix this, you would need to add a closing quote to the end of the string:
```
my_string = '''
this is a triple-quoted string
and now it has a closing quote'''
```
File "test.py", line 9 return mark ^ SyntaxError: 'return' outside function
这个错误提示是因为在一个函数外部使用了`return`语句,可能是因为缩进不正确导致的。请检查代码缩进是否正确,确保`return`语句在函数内部使用。另外,你的代码中`j`没有定义,应该是一个变量名错误,应该改为`i`。将这两个问题进行修正后的代码如下所示:
```python
def is_prime(n):
"""
判断素数的函数,接收一个正整数为参数,参数是素数时返回True,否则返回False。
减小判定区间,减少循环次数,提升效率
"""
for i in range(2,n+1):
mark=True
for j in range(2,int(i**0.5)+1):
if i%j==0:
mark=False
if mark:
return True
return False
```
这个函数可以判断一个正整数是否为素数。