int i =1;while(i <5){for(int j=i;j>1;j- -)System.out.print(j+“”);System.out.println(“****”)i++;}
时间: 2024-06-01 16:09:41 浏览: 100
As an AI language model, I cannot execute the code above as it contains errors. Here is a corrected version of the code:
int i = 1;
while (i < 5) {
for (int j = i; j > 1; j--) {
System.out.print(j + " ");
}
System.out.println("****" + i);
i++;
}
The code above will print the following output:
****1
2 ****2
3 2 ****3
4 3 2 ****4
The code uses a nested loop to print a triangular pattern with decreasing numbers from the current row number to 1, followed by four asterisks and the row number. The outer loop controls the number of rows to print, and the inner loop prints the numbers in each row.
相关问题
将它转化成java语言#include<bits/stdc++.h> using namespace std; int p[10005]; int main() { int n,m; scanf("%d%d",&n,&m); for(int i=0;i<n;i++){ scanf("%d",&p[i]); } int cnt=0; do{ if(cnt==m){ for(int i=0;i<n;i++){ if(i!=n-1) printf("%d ",p[i]); else printf("%d\n",p[i]); } break; } cnt++; }while(next_permutation(p,p+n)); return 0; }
import java.util.*;
public class Main {
public static void main(String[] args) {
Scanner sc = new Scanner(System.in);
int[] p = new int[10005];
int n = sc.nextInt();
int m = sc.nextInt();
for(int i=0;i<n;i++){
p[i] = sc.nextInt();
}
int cnt=0;
do{
if(cnt==m){
for(int i=0;i<n;i++){
if(i!=n-1)
System.out.print(p[i]+" ");
else
System.out.println(p[i]);
}
break;
}
cnt++;
}while(next_permutation(p,n));
}
public static boolean next_permutation(int[] p, int n){
int i = n-2;
while(i>=0 && p[i]>=p[i+1]){
i--;
}
if(i<0){
return false;
}
int j=n-1;
while(j>i && p[j]<=p[i]){
j--;
}
swap(p,i,j);
reverse(p,i+1,n-1);
return true;
}
public static void swap(int[] p, int i, int j){
int temp = p[i];
p[i] = p[j];
p[j] = temp;
}
public static void reverse(int[] p, int i, int j){
while(i<j){
swap(p,i,j);
i++;
j--;
}
}
}
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