for (int i = 0; i < 6; i++) { int k = ++i; while (k < 5) { System.out.print(i); break; } }
时间: 2024-05-13 17:06:26 浏览: 15
This code will result in an infinite loop because the increment section of the for loop is missing (i++ or i+=1).
Here is the corrected code:
for (int i = 0; i < 6; i++) {
int k = i;
while (k < 5) {
System.out.print(i);
break;
}
}
This code will print the numbers 0, 1, 2, 3, 4, 5 on separate lines because it loops through 6 times (0 to 5) and for each iteration, it prints the value of i once (due to the break statement in the while loop).
相关问题
for (int i = 0; i <= 3; i++) 什么意思
这是一个简单的 for 循环语句,其中 i 的初始值为 0,每次循环 i 的值增加 1,直到 i 的值等于 4 时退出循环。循环体内的代码将会被执行 4 次。可以写成等价的 while 循环:
```
int i = 0;
while (i <= 3) {
// 循环体内的代码
i++;
}
```
#include<stdio.h> int booth[401],t[401][401],dp[401]; int main() { int n; scanf("%d",&n); for(int i=0;i<n;i++) scanf("%d",&booth[i]); for(int i=0;i<n;i++) for(int j=0;j<n;j++) scanf("%d",&t[i][j]); for(int i=0;i<n;i++) if(t[0][i]<=booth[i]) dp[i]=1; int flag=1; while(flag) { flag=0; for(int i=0;i<n;i++) { for(int j=0;j<n;j++) { if(t[i][j]<=(booth[j]-booth[i])&&dp[j]<=dp[i]&&i!=j) { dp[j]=dp[i]+1; flag=1; } } } } int ans=0; for(int i=0;i<n;i++) if(ans<dp[i]) ans=dp[i]; printf("%d",ans); return 0; }转换为c++代码
以下是将给定的 C 代码转换为 C++ 代码后的结果:
```cpp
#include <iostream>
using namespace std;
int booth[401], t[401][401], dp[401];
int main() {
int n;
cin >> n;
for (int i = 0; i < n; i++)
cin >> booth[i];
for (int i = 0; i < n; i++)
for (int j = 0; j < n; j++)
cin >> t[i][j];
for (int i = 0; i < n; i++)
if (t[0][i] <= booth[i])
dp[i] = 1;
int flag = 1;
while (flag) {
flag = 0;
for (int i = 0; i < n; i++) {
for (int j = 0; j < n; j++) {
if (t[i][j] <= (booth[j] - booth[i]) && dp[j] <= dp[i] && i != j) {
dp[j] = dp[i] + 1;
flag = 1;
}
}
}
}
int ans = 0;
for (int i = 0; i < n; i++)
if (ans < dp[i])
ans = dp[i];
cout << ans << endl;
return 0;
}
```
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