请给一个可以玩超级玛丽的python 代码

好的，以下是一个简单的使用Python实现的超级玛丽游戏代码：

import pygame

# 初始化pygame
pygame.init()

# 设置游戏窗口大小
win = pygame.display.set_mode((500, 480))

# 给游戏窗口设置标题
pygame.display.set_caption("Super Mario")

# 加载玛丽图片
walkRight = [pygame.image.load('R1.png'), pygame.image.load('R2.png'), pygame.image.load('R3.png'), pygame.image.load('R4.png'), pygame.image.load('R5.png'), pygame.image.load('R6.png'), pygame.image.load('R7.png'), pygame.image.load('R8.png'), pygame.image.load('R9.png')]
walkLeft = [pygame.image.load('L1.png'), pygame.image.load('L2.png'), pygame.image.load('L3.png'), pygame.image.load('L4.png'), pygame.image.load('L5.png'), pygame.image.load('L6.png'), pygame.image.load('L7.png'), pygame.image.load('L8.png'), pygame.image.load('L9.png')]
bg = pygame.image.load('bg.jpg')
char = pygame.image.load('standing.png')

# 设置游戏时钟
clock = pygame.time.Clock()

# 定义玛丽的起始位置和速度
x = 50
y = 400
width = 64
height = 64
vel = 5

# 定义玛丽的移动状态
isJump = False
jumpCount = 10
left = False
right = False
walkCount = 0

# 绘制游戏窗口
def redrawGameWindow():
    global walkCount
    win.blit(bg, (0,0))

    if walkCount + 1 >= 27:
        walkCount = 0

    if left:
        win.blit(walkLeft[walkCount//3], (x,y))
        walkCount += 1
    elif right:
        win.blit(walkRight[walkCount//3], (x,y))
        walkCount += 1
    else:
        win.blit(char, (x,y))

    pygame.display.update()

# 游戏循环
run = True
while run:
    clock.tick(27)

    for event in pygame.event.get():
        if event.type == pygame.QUIT:
            run = False

    keys = pygame.key.get_pressed()

    if keys[pygame.K_LEFT] and x > vel:
        x -= vel
        left = True
        right = False
    elif keys[pygame.K_RIGHT] and x < 500 - width - vel:
        x += vel
        left = False
        right = True
    else:
        left = False
        right = False
        walkCount = 0

    if not (isJump):
        if keys[pygame.K_SPACE]:
            isJump = True
            left = False
            right = False
            walkCount = 0
    else:
        if jumpCount >= -10:
            neg = 1
            if jumpCount < 0:
                neg = -1
            y -= (jumpCount ** 2) * 0.5 * neg
            jumpCount -= 1
        else:
            isJump = False
            jumpCount = 10

    redrawGameWindow()

# 退出pygame
pygame.quit()

请注意，这只是一个简单的示例代码，可能还有很多可以改进的地方。同时，在运行此代码之前，您需要准备好超级玛丽的素材图片，并将其放置在与代码文件相同的目录下。