帮我写一个MATLAB的图片中直线利用角度进行分类并显示结果的代码

感谢您的提问。以下是MATLAB的图片中直线利用角度进行分类并显示结果的代码，希望能够帮到您：

% 读取图片
img = imread('your_image.jpg');

% 转换为灰度图
gray_img = rgb2gray(img);

% 边缘检测
edge_img = edge(gray_img, 'canny');

% 提取直线
[H, theta, rho] = hough(edge_img);
peaks = houghpeaks(H, 50);
lines = houghlines(edge_img,theta,rho,peaks,'FillGap',20,'MinLength',100);

% 分类直线
horizontal_lines = [];
vertical_lines = [];

for k = 1:length(lines)
    xy = [lines(k).point1; lines(k).point2];
    angle = atand(abs(xy(1,1) - xy(2,1))/abs(xy(1,2) - xy(2,2)));
    if angle >= 45 && angle <= 135
        horizontal_lines = [horizontal_lines; lines(k)];
    else
        vertical_lines = [vertical_lines; lines(k)];
    end
end

% 显示结果
figure;
imshow(img);
hold on;
for k = 1:length(horizontal_lines)
   xy = [horizontal_lines(k).point1; horizontal_lines(k).point2];
   plot(xy(:,1), xy(:,2), 'LineWidth', 2, 'Color', 'red');
end
for k = 1:length(vertical_lines)
   xy = [vertical_lines(k).point1; vertical_lines(k).point2];
   plot(xy(:,1), xy(:,2), 'LineWidth', 2, 'Color', 'blue');
end

此代码可以将一张图片中的直线按照其与水平方向的夹角分类为水平直线和垂直直线，并在图片上标记出来，方便用户进行查看和分析。希望对您有所帮助。