使用索引和切片完成下列操作,如果使用列表推导有加分 创建如下图所示列表 [[0, 1, 2, 3, 4], [10, 11, 12, 13, 14], [20, 21, 22, 23, 24], [30, 31, 32, 33, 34], [40, 41, 42, 43, 44]]
时间: 2023-07-27 21:32:34 浏览: 33
1. 获取第二行第三个元素,即 12
```
lst = [[0, 1, 2, 3, 4], [10, 11, 12, 13, 14], [20, 21, 22, 23, 24], [30, 31, 32, 33, 34], [40, 41, 42, 43, 44]]
element = lst[1][2]
print(element)
```
2. 获取第四行第一列到第三列的元素,即 [30, 31, 32]
```
lst = [[0, 1, 2, 3, 4], [10, 11, 12, 13, 14], [20, 21, 22, 23, 24], [30, 31, 32, 33, 34], [40, 41, 42, 43, 44]]
row = lst[3]
elements = row[0:3]
print(elements)
```
3. 获取第一列所有元素,即 [0, 10, 20, 30, 40]
```
lst = [[0, 1, 2, 3, 4], [10, 11, 12, 13, 14], [20, 21, 22, 23, 24], [30, 31, 32, 33, 34], [40, 41, 42, 43, 44]]
column = [row[0] for row in lst]
print(column)
```
4. 获取第二行所有元素,即 [10, 11, 12, 13, 14]
```
lst = [[0, 1, 2, 3, 4], [10, 11, 12, 13, 14], [20, 21, 22, 23, 24], [30, 31, 32, 33, 34], [40, 41, 42, 43, 44]]
row = lst[1]
print(row)
```
5. 获取第三列所有元素,即 [2, 12, 22, 32, 42]
```
lst = [[0, 1, 2, 3, 4], [10, 11, 12, 13, 14], [20, 21, 22, 23, 24], [30, 31, 32, 33, 34], [40, 41, 42, 43, 44]]
column = [row[2] for row in lst]
print(column)
```
使用列表推导的方式:
```
lst = [[i*5+j for j in range(5)] for i in range(5)]
print(lst)
```
输出:
```
[[0, 1, 2, 3, 4], [5, 6, 7, 8, 9], [10, 11, 12, 13, 14], [15, 16, 17, 18, 19], [20, 21, 22, 23, 24]]
```
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