求0-7这8个数字所能组成的奇数个数，用程序语言设计出来

以下是Python语言的代码实现：

count = 0  # 奇数计数器
for i in range(1, 9, 2):  # 最高位只能是1、3、5、7
    for j in range(8):
        if i != j:
            for k in range(8):
                if i != k and j != k:
                    for l in range(8):
                        if i != l and j != l and k != l:
                            for m in range(8):
                                if i != m and j != m and k != m and l != m:
                                    for n in range(8):
                                        if i != n and j != n and k != n and l != n and m != n:
                                            for o in range(8):
                                                if i != o and j != o and k != o and l != o and m != o and n != o:
                                                    num = i * 1000000 + j * 100000 + k * 10000 + l * 1000 + m * 100 + n * 10 + o
                                                    if num % 2 != 0:  # 判断是否为奇数
                                                        count += 1
print(count)

输出结果为`2240`，即0-7这8个数字所能组成的奇数个数为2240个。