Which role does the class HouseBlend correspond to In the design of the ording system for Starbuzz Coffee?

The class HouseBlend corresponds to one of the options for coffee in the ordering system for Starbuzz Coffee. It is one of the four types of coffee, along with Dark Roast, Decaf, and Espresso.

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链接：https://ac.nowcoder.com/acm/contest/59935/B 来源：牛客网 It's New Year's Day, and it was a tradition for ancient Chinese to write couplets. Sometimes one person would give the first line, and another person would need to come up with the second line based on the sentence structure and meaning, which requires considerable literary skills. Now given a first line of length nn, with each character represented by a number for convenience, you need to write a second line that meets the following requirements: 1. Each number in the second line must be a positive integer. 2. Each number in the second line must not appear in the first line. 3. The ii-th number in the first line corresponds to the ii-th number in the second line. You can specify the correspondence relationship arbitrarily, but the relationship must be consistent and unique. For example, if you specify that the number 3 in the first line corresponds to the number 1 in the second line, then another non-3 number in the first line cannot correspond to the number 1, and all 3s in the first line must correspond to 1.用c++给我把这道题做出来

好的，这道题目可以使用一个桶来记录第一行中出现的数字，然后从1到n遍历，如果该数字没有在桶中出现过，则将其加入到第二行中，并在桶中标记该数字已经出现过。具体实现可以参考以下代码：

#include <iostream>
#include <vector>
using namespace std;

int main() {
    int n;
    cin >> n;
    vector<int> first(n);
    vector<bool> used(n + 1, false);
    for (int i = 0; i < n; i++) {
        cin >> first[i];
        used[first[i]] = true; // 记录第一行中出现的数字
    }
    vector<int> second(n);
    for (int i = 1; i <= n; i++) {
        if (!used[i]) {
            second[first[i - 1] - 1] = i; // 根据题目要求，第i个数字对应第i个位置
        }
    }
    for (int i = 0; i < n; i++) {
        cout << second[i] << " ";
    }
    cout << endl;
    return 0;
}

希望能帮到你！

We consider in this exercise the validation of a Sudoku grid. The Sudoku a mathematical game. You do not need to know this game to make this exercise. A solved Sudoku grid is represented on the right. It is a grid composed of 9 lines and 9 columns. A grid is said to be valid if it respects the following rules : • each line contains exactly once each value from 1 to 9 • each column contains exactly once each value from 1 to 9 • each block contains exactly once each value from 1 to 9. A block is a square of 3 × 3 cells. There are 9 blocks in the grid, they are delimited in the example grid with the bold lines. Q1) Create a class Sudoku containing a main() method. Declare a variable named grid corresponding to a sudoku grid. Your grid may correspond to the example which is valid, or not (for example an invalid grid filled with 1's). Q2) Write a static function named validLine() that has two parameters : a grid and a line index i. This function checks if the line i is valid (i.e. contains exactly once each value from 1 to 9) or not. It may be useful to write and use another function that counts the number of occurrences of a given value k in the line i. Q3) Write a static method allLinesValid() that takes a grid as parameter and checks if all the lines are valid. You may use the previous method, even if you did not write it.

Sure, I can help with that! Here's the implementation of the Sudoku class with the main() method, validLine() static method, and allLinesValid() static method:

class Sudoku:
    def main(self):
        # Declare a variable named grid corresponding to a sudoku grid
        grid = [
            [5, 3, 4, 6, 7, 8, 9, 1, 2],
            [6, 7, 2, 1, 9, 5, 3, 4, 8],
            [1, 9, 8, 3, 4, 2, 5, 6, 7],
            [8, 5, 9, 7, 6, 1, 4, 2, 3],
            [4, 2, 6, 8, 5, 3, 7, 9, 1],
            [7, 1, 3, 9, 2, 4, 8, 5, 6],
            [9, 6, 1, 5, 3, 7, 2, 8, 4],
            [2, 8, 7, 4, 1, 9, 6, 3, 5],
            [3, 4, 5, 2, 8, 6, 1, 7, 9]
        ]

        # Check if the grid is valid
        print(self.isValid(grid))

    @staticmethod
    def validLine(grid, i):
        # Check if the line i is valid (i.e. contains exactly once each value from 1 to 9)
        for j in range(1, 10):
            if grid[i].count(j) != 1:
                return False
        return True

    @staticmethod
    def allLinesValid(grid):
        # Check if all the lines are valid
        for i in range(0, 9):
            if not Sudoku.validLine(grid, i):
                return False
        return True

    def isValid(self, grid):
        # Check if the grid is valid (i.e. each line, column, and block contains exactly once each value from 1 to 9)
        for i in range(0, 9):
            # Check if the line i is valid
            if not Sudoku.validLine(grid, i):
                return False

            # Check if the column i is valid
            column = [grid[j][i] for j in range(0, 9)]
            if not Sudoku.validLine(column, 0):
                return False

            # Check if the block i is valid
            block = []
            for j in range(0, 3):
                for k in range(0, 3):
                    block.append(grid[(i // 3) * 3 + j][(i % 3) * 3 + k])
            if not Sudoku.validLine(block, 0):
                return False

        return True

To test the implementation, you can create an instance of the Sudoku class and call the main() method:

sudoku = Sudoku()
sudoku.main()

This will output True if the grid is valid, and False otherwise.