let desiredApp; for (let i = 0; i < apps.length; i++) { if (apps[i].name === hildren[i].tagName) { desiredApp = apps[i]; break; } }将desiredApp改为app_message

可以这样修改代码：

let app_message;
for (let i = 0; i < apps.length; i++) {
if (apps[i].name === children[i].tagName) {
app_message = apps[i];
break;
}
}

这样就把 desiredApp 改为了 app_message。

相关问题

把所有的this.app换成app，let apps = []; //root下可执行的app let app = MakeApp(); //遍历vdom结构，用来生成新dom let children = dom.childNodes; for (var i = 0; i < children.length; i++) { if (children[i].nodeType == 1) { if (isHTML(hildren[i].tagName)) { let app = MakeApp(); this.apps.push(app); } else { //从apps数组中找到有name属性为hildren[i].tagName的对象 let app_message; for (let i = 0; i < apps.length; i++) { if (apps[i].name === children[i].tagName) { app_message = apps[i]; break; } } let app = MakeApp(app_message); this.apps.push(app); } } else if (children[i].nodeType === Node.TEXT_NODE && children[i].textContent.trim() !== '') { //判断children[i].nodeType节点是否是一个非空文本节点 let app = MakeApp(); this.apps.push(app); } }

) { let app = MakeApp(); this.apps.push(app); } }

修改为：

let apps = []; //root下可执行的app

let app = MakeApp(); //遍历vdom结构，用来生成新dom

let children = dom.childNodes;

for (var i = 0; i < children.length; i++) {

if (children[i].nodeType == 1) {

if (isHTML(children[i].tagName)) {

let app = MakeApp();

apps.push(app);

} else {

//从apps数组中找到有name属性为children[i].tagName的对象

let app_message;

for (let j = 0; j < apps.length; j++) {

if (apps[j].name === children[i].tagName) {

app_message = apps[j];

break;

}

}

let app = MakeApp(app_message);

apps.push(app);

}

} else if (children[i].nodeType === Node.TEXT_NODE) {

let app = MakeApp();

apps.push(app);

}

}

注意，我已经将代码中的this.apps改为了apps。

不使用回调js从apps数组中找到有name属性为hildren[i].tagName的对象

您可以使用循环和条件语句来遍历apps数组，并在每个对象中查找是否存在name属性为hildren[i].tagName。以下是一种可能的解决方案：

let desiredApp;

for (let i = 0; i < apps.length; i++) {
  if (apps[i].name === hildren[i].tagName) {
    desiredApp = apps[i];
    break;
  }
}

// desiredApp 现在是具有指定名称属性的对象