c语言程序设计21点扑克牌,c语言程序设计 21点扑克牌游戏

以下是一个简单的C语言程序设计21点扑克牌游戏的代码：

#include <stdio.h>
#include <stdlib.h>
#include <time.h>

int main()
{
    int player_score = 0, dealer_score = 0;
    int player_cards[5], dealer_cards[5];
    int player_card_count = 0, dealer_card_count = 0;
    int i, card;

    srand(time(NULL));

    // 初始化玩家和庄家的手牌
    player_cards[player_card_count++] = rand() % 13 + 1;
    dealer_cards[dealer_card_count++] = rand() % 13 + 1;

    // 玩家先抽一张牌
    player_cards[player_card_count++] = rand() % 13 + 1;
    player_score = player_cards[0] + player_cards[1];

    printf("你的手牌: %d %d (总分: %d)\n", player_cards[0], player_cards[1], player_score);

    // 庄家抽一张牌
    dealer_cards[dealer_card_count++] = rand() % 13 + 1;
    dealer_score = dealer_cards[0];

    printf("庄家的手牌: %d ? (总分: ?)\n", dealer_cards[0]);

    // 玩家决定是否继续抽牌
    while (player_score < 21) {
        printf("是否继续抽牌 (y/n)? ");
        char choice;
        scanf(" %c", &choice);

        if (choice == 'n') {
            break;
        }

        card = rand() % 13 + 1;
        player_cards[player_card_count++] = card;
        player_score += card;

        printf("你抽到了 %d (总分: %d)\n", card, player_score);
    }

    // 庄家继续抽牌直到总分大于等于17
    while (dealer_score < 17) {
        card = rand() % 13 + 1;
        dealer_cards[dealer_card_count++] = card;
        dealer_score += card;
    }

    // 输出庄家的手牌和总分
    printf("庄家的手牌: ");
    for (i = 0; i < dealer_card_count; i++) {
        printf("%d ", dealer_cards[i]);
    }
    printf("(总分: %d)\n", dealer_score);

    // 判断胜负
    if (player_score > 21) {
        printf("你爆了，庄家获胜！\n");
    } else if (dealer_score > 21) {
        printf("庄家爆了，你获胜！\n");
    } else if (player_score > dealer_score) {
        printf("你的总分大于庄家，你获胜！\n");
    } else if (player_score < dealer_score) {
        printf("你的总分小于庄家，庄家获胜！\n");
    } else {
        printf("你和庄家的总分相同，平局！\n");
    }

    return 0;
}

这个程序使用了随机数生成器来模拟扑克牌的抽取。玩家先抽两张牌，然后可以选择是否继续抽牌，直到总分大于等于21或者选择停止抽牌。庄家会先抽一张牌，然后根据规则继续抽牌，直到总分大于等于17。最后程序会判断双方的总分，输出胜负结果。