使用Java将下述{ "class": "1A", "teacher": "Mr. Smith", "students": [ { "name": "Alice", "age": 12, "gender": "female" }, { "name": "Bob", "age": 13, "gender": "male" } ] }json串中的students数组转换成对象并打印对象

好的，您可以使用Java中的JSON库解析JSON字符串，然后获取到students数组对应的JSONArray对象，再遍历JSONArray中的每个元素，将其转换为JSONObject对象。最后可以打印出每个JSONObject对象对应的Java对象，代码实现如下：

import org.json.JSONArray;
import org.json.JSONObject;

public class Main {
    public static void main(String[] args) {
        String jsonString = "{ \"class\": \"1A\", \"teacher\": \"Mr. Smith\", \"students\": [ { \"name\": \"Alice\", \"age\": 12, \"gender\": \"female\" }, { \"name\": \"Bob\", \"age\": 13, \"gender\": \"male\" } ] }";
        JSONObject jsonObject = new JSONObject(jsonString);
        JSONArray studentsArray = jsonObject.getJSONArray("students");
        for (int i = 0; i < studentsArray.length(); i++) {
            JSONObject studentObject = studentsArray.getJSONObject(i);
            String name = studentObject.getString("name");
            int age = studentObject.getInt("age");
            String gender = studentObject.getString("gender");
            Student student = new Student(name, age, gender);
            System.out.println(student);
        }
    }
}

class Student {
    private String name;
    private int age;
    private String gender;

    public Student(String name, int age, String gender) {
        this.name = name;
        this.age = age;
        this.gender = gender;
    }

    @Override
    public String toString() {
        return "Student{" +
                "name='" + name + '\'' +
                ", age=" + age +
                ", gender='" + gender + '\'' +
                '}';
    }
}

运行结果如下：

Student{name='Alice', age=12, gender='female'}
Student{name='Bob', age=13, gender='male'}

其中，Student类是自定义的Java类，用于存储每个学生的信息。在遍历JSONArray对象时，可以通过调用getXXX()方法获取JSONObject对象中的属性值，并根据这些属性值创建新的Java对象。